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2 years ago

Which lists the amplitudes of sound waves from these sources in order from greatest to least?

Physics

2 answers:

KIM [24]2 years ago

7 0

<h2>Answer:</h2>

The correct answer is option B which is a chainsaw, diesel truck, rustling leaves.

<h3>Explanation:</h3>

The amplitude of the sound wave is the maximum displacement of the particles from their resting position.
Higher the amplitude means high sound.
So the sound of a chainsaw is high, so its amplitude will be great and after that the amplitude of diesel truck is high and rustling leaves have the lowest amplitude.

nignag [31]2 years ago

5 0

The correct option is:

<span>chainsaw, diesel truck, rustling leaves

In fact, this option lists the sounds from greatest amplitude (which means, greatest loudness) to smallest amplitude. For comparison, this is the intensity of the three different sounds:
- chain saw: approximately 120 dB
- diesel truck: approximately 80 dB
- rustling leaves: approximately 20 dB

(values taken from this table: </span>https://www.chem.purdue.edu/chemsafety/Training/PPETrain/dblevels.htm )

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if two point charges are separated by 1.5 cm and have charge values of 2.0 and -4.0, respectively, what is the value of the mutu

RUDIKE [14]

Complete question:

if two point charges are separated by 1.5 cm and have charge values of +2.0 and -4.0 μC, respectively, what is the value of the mutual force between them.

Answer:

The mutual force between the two point charges is 319.64 N

Explanation:

Given;

distance between the two point charges, r = 1.5 cm = 1.5 x 10⁻² m

value of the charges, q₁ and q₂ = 2 μC and - μ4 C

Apply Coulomb's law;

$F = \frac{k|q_1||q_2|}{r^2}$

where;

F is the force of attraction between the two charges

|q₁| and |q₂| are the magnitude of the two charges

r is the distance between the two charges

k is Coulomb's constant = 8.99 x 10⁹ Nm²/C²

$F = \frac{k|q_1||q_2|}{r^2} \\\\F = \frac{8.99*10^9 *4*10^{-6}*2*10^{-6}}{(1.5*10^{-2})^2} \\\\F = 319.64 \ N$

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