What is the molar concentration of the Cl⁻ ions in 0.64 M MgCl2(aq)?
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Answer:
20619.4793 years
Explanation:
The half life of carbon-14 = 5730 years
The formula for the half life for a first order kinetic reaction is:
Where,
is the half life
k is the rate constant.
Thus rate constant is:
5730 years=ln(2)/k
k = 1.21×10⁻⁴ years ⁻¹
Using integrated rate law as:
Where,
is the concentration at time t
is the initial concentration
Given that the final concentration contains 8.25 % of the original quantity which means that:
So,
ln(.0825)= -1.21×10⁻⁴×t
<u> t = 20619.4793 years</u>
<u></u>
1.70 × 10³ seconds
<h3>Explanation </h3> + 2 e⁻ →
It takes two moles of electrons to reduce one mole of cobalt (II) ions and deposit one mole of cobalt.
Cobalt has an atomic mass of 58.933 g/mol. 0.500 grams of Co contains of Co atoms. It would take
of electrons to reduce cobalt (II) ions and produce the
of cobalt atoms.
Refer to the Faraday's constant, each mole of electrons has a charge of around 96 485 columbs. The 0.01697 mol of electrons will have a charge of . A current of 0.961 A delivers 0.961 C of charge in one single second. It will take
to transfer all these charge and deposit 0.500 g of Co.