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Volgvan
3 years ago
5

All recorded measurements require a number followed by a _______ .

Physics
1 answer:
Dmitry [639]3 years ago
7 0
Answer: unit

Jusitification:

An plain number does not inform the real meaning of the measure if you do not inform the unit of measurement.

Without the unit you cannot tell the real magnitude of objects or phenomena measured.

For example, suppose that some one asks how long is a boat and the answer is 20. What is it? 20 meters? 20 feet? 20 yards? You do not really know if it is a big boat or a small one until you inform the unit of measurement.

The same is true with any measurement. If you measure volumen you have to tell is the number reported is galon, liters, cubic centimeter, mililiter, cubir meter, or what.
You might be interested in
Cual es la fuerza de empuje que recibe un cuerpo de forma cilíndrica que mide 0.3 m de radio y 8m de altura, el cual se sumerge
zimovet [89]

Responder:

Fb = 17,5 kN

Explicación:

La expresión de la fuerza de empuje

Fb = ρgV ---------- 1

dónde

Fb = fuerza de flotación

ρ = densidad del fluido

g = aceleración debida a la gravedad

V = volumen de fluido

Paso uno:

datos dados

radio del cilindro = 0,3 m

altura h = 8m

densidad = 790 kg / m ^ 3

g = 9,8 m / s ^ 2

El volumen del cilindro se expresa como

V = πr ^ 2h

V = 3,142 * 0,3 ^ 2 * 8

V = 3,142 * 0,09 * 8

V = 2,26

El volumen es 2.26m ^ 3, el volumen del cilindro es igual al volumen de alcohol disparado

La expresión de la fuerza de empuje es

Fb = ρgV

sustituyendo tenemos

Fb = 790 * 9,8 * 2,26

Fb = 17514,26N

Fb = 17,5 kN

3 0
4 years ago
Calculate the number of millimeters in 2.13 kilometer.
lapo4ka [179]

The answer is 2,130,000

6 0
4 years ago
1. What is weather?
Fynjy0 [20]
Weather is rain sun snow storm and warm and cold
6 0
3 years ago
Read 2 more answers
The current theory of the structure of the
IRISSAK [1]

1) The mass of the continent is 3.3\cdot 10^{21} kg

2) The kinetic energy of the continent is 624 J

3) The speed of the jogger must be 4 m/s

Explanation:

1)

We start by finding the volume of the continent. We have:

L = 5850 km = 5.85\cdot 10^6 m is the side

t = 35 km = 3.5\cdot 10^4 m is the depth

So the volume is

V=L^2 t = (5.85\cdot 10^6)^2 (3.5\cdot 10^4)=1.20\cdot 10^{18} m^3

We also know that its density is

d=2750 kg/m^3

Therefore, we can find the mass by multiplying volume by density:

m=dV=(2750)(1.20\cdot 10^{18})=3.3\cdot 10^{21} kg

2)

The kinetic energy of the continent is given by:

K=\frac{1}{2}mv^2

where

m=3.3\cdot 10^{21} kg is its mass

v = 3.2 cm/year is the speed

We have to convert the speed into m/s. We have:

3.2 cm = 0.032 m

1 year = 1(365)(24)(60)(60)=3.15\cdot 10^7 s

So, the speed is:

v=\frac{0.032 m}{3.15 \cdot 10^7 s}=1.02\cdot 10^{-9} m/s

So, we can now find the kinetic energy:

K=\frac{1}{2}(1.20\cdot 10^{21})(1.02\cdot 10^{-9})^2=624 J

3)

Here we have a jogger of mass

m = 78 kg

And the jogger has the same kinetic energy of the continent, so

K = 624 J

The kinetic energy of the jogger is given by

K=\frac{1}{2}mv^2

where v is the speed of the jogger.

Solving for v, we find the speed that the jogger must have:

v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(624)}{78}}=4 m/s

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

3 0
3 years ago
) Force F = − + ( 8.00 N i 6.00 N j ) ( ) acts on a particle with position vector r = + (3.00 m i 4.00 m j ) ( ) . What are (a)
natali 33 [55]

To develop this problem it is necessary to apply the concepts related to the Cross Product of two vectors as well as to obtain the angle through the magnitude of the angles.

The vector product between the Force and the radius allows us to obtain the torque, in this way,

\tau = \vec{F} \times \vec{r}

\tau = (8i+6j)\times(-3i+4j)

\tau = (8*4)(i\times j)+(6*-3)(j\times i)

\tau = 32k +18k

\tau = 50 k

Therefore the torque on the particle about the origen is 50k

PART B) To find the angle between two vectors we apply the definition of the dot product based on the vector quantities, that is,

cos\theta = \frac{r\cdot F}{|\vec{r}|*|\vec{F}|}

cos\theta = \frac{(8*-3)+(4*3)}{\sqrt{(-3)^2+4^2}*\sqrt{8^2+6^2}}

cos\theta = -0.24

\theta = cos^{-1} (-0.24)

\theta = 103.88\°

Therefore the angle between the ratio and the force is 103.88°

5 0
3 years ago
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