Answer:
Explanation:
angular acceleration α = 6.61 / 8.97 = .737 rad / s²
moment of inertia = 1/3 m L²
= 1/3 x 1.13 x .899²
= .3045 kg m²
torque applied = moment of inertia x angular acceleration
= .737 x .3045 = .2244
If be the force
Torque
= F x .899 = .2244
F = .25 N ,
You are sitting at the center of a large turntable at an amusement park as it is set spinning freely. You decide to crawl towards the edge of the turntable. Rotational speed will decrease
There is no external torque
hence , the angular momentum of the table is conserved
L (initial) = L ( final)
since , L = m*v*r
where
m = mass
v = velocity
r = radius
If the person is crawled towards the outer rim, then the rotational inertia of the turntable will increase. In order to conserve the angular momentum , its rotational speed will decrease as mass and radius cannot be altered .
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Answer:
Vx = 3.10 [m/s]
Vy = 11.59 [m/s]
Explanation:
To solve this problem we must decompose the velocity vector by means of the angle on the horizontal.
v = 12 [m/s]
Vx = 12*cos (75) = 3.10 [m/s]
Vy = 12*sin (75) = 11.59 [m/s]
