Question

If 9.71 mL of 0.252 KOH is used to complete titrate 15.0 mL of HCL , how many moles of HCL are in the solution ?

Answer 1

Answer:

0.00245 moles of HCl

Explanation:

We are given;

Volume of KOH = 9.71 mL

Molarity of KOH = 0.252 M

Volume of HCl = 15.0 mL

We are required to determine the number of moles of HCl  

Step 1: Write the balanced equation for the reaction

The reaction between HCl and KOH is given by;

KOH(aq) + HCl(aq) → KCl(aq) + H₂O(l)

Step 2: Calculating the number of moles of KOH

Molarity = Moles ÷ Volume

Rearranging the formula;

Moles = Molarity × Volume

          = 0.252 M × 0.00971 L

          = 0.00245 moles

Step 3: Moles of HCl

From the equation, 1 mole of KOH reacts with 1 mole of HCl

Therefore, the mole ratio of KOH : HCl is 1 : 1

Thus,

Moles of HCl will be 0.00245 moles

Therefore, there are 0.00245 moles of HCl in the solution.