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skad [1K]
3 years ago
7

All of the following are uses of a lake/pond except:

Chemistry
1 answer:
umka2103 [35]3 years ago
6 0
Well give me the options lol
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How much of a 2.0 M NaCl solution is needed to make 205.0 mL of 0.15 M NaCl solution?
svetlana [45]

Answer:

<h3>Step 1: </h3>

To relate the volume and molarity of a solution at two different concentrations, the expression used is :

M₁V₁ = M₂V₂

<h3>step 2:</h3>

(2M) V₁ = (0.15M)(250ML)

V₁ = 18.75

step 3:

<h2>Pls, branliest! :)</h2>
5 0
3 years ago
How many moles of KF are present in 46.5 grams of KF
irinina [24]

Explanation:

here's the answer to your question

4 0
3 years ago
Read 2 more answers
O 1. 12 moles
mars1129 [50]

Answer:

n_{H_2O}=5.94molH_2O

Explanation:

Hello there!

In this case, according to the given question about stoichiometry, it is possible for us to calculate the required moles of water that will be produced by 12 grams of hydrogen, by using the molar mass of this reactant (2.02 g/mol as it is diatomic) and the 2:2 mole ratio in the chemical equation by solving the following setup:

n_{H_2O}=12gH_2*\frac{1molH_2}{2.02gH_2} *\frac{2molH_2O}{2molH_2} \\\\n_{H_2O}=5.94molH_2O

Regards!

3 0
2 years ago
N2(g) + 3H2(g) → 2NH3(g) How many grams of N2 are required to produce 240.0g NH3?
just olya [345]

Answer:

\large \boxed{\text{197.4 g}}

Explanation:

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ:     28.01               17.03

            N₂ + 3H₂ ⟶ 2NH₃

m/g:                          240.0

(a) Moles of NH₃

\text{Moles of NH}_{3} = \text{240.0 g NH}_{3}\times \dfrac{\text{1 mol NH}_{3}}{\text{17.03 g NH}_{3}}= \text{14.09 mol NH}_{3}

(b) Moles of N₂

\text{Moles of N$_{2}$} = \text{14.09 mol NH}_{3} \times \dfrac{\text{1 mol N$_{2}$}}{\text{2 mol NH}_{3}} = \text{7.046 mol N$_{2}$}

(c) Mass of N₂

\text{Mass of N$_{2}$} =\text{7.046 mol N$_{2}$} \times \dfrac{\text{28.01 g N$_{2}$}}{\text{1 mol N$_{2}$}} = \textbf{197.4 g N$_{2}$}\\\\\text{The reaction requires $\large \boxed{\textbf{197.4 g}}$ of N$_{2}$}

7 0
3 years ago
Read 2 more answers
Why don't some people want a relationship with God?
mr_godi [17]
Some fear that they won't be able to have fun anymore if they accept God, some are afraid of what others might think of them if they accept God, some think they are too messed up to have a relationship with God, and the list goes on and on. Who knows why someone would refuse.
Hope this helps~!
~{Oh Mrs.Believer}
6 0
3 years ago
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