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son4ous [18]
3 years ago
11

If the compound potassium chloride is written in words, how do you know to write the formula with one potassium and one chloride

Chemistry
1 answer:
NNADVOKAT [17]3 years ago
6 0

Because there is only one stable ionic compound made up of potassium and chlorine, and that is KCl. So calling is "mono chloride" or similar would be redundant assuming you understand basic chemistry (i.e. knowing oxidation numbers of K is +1 and Cl is -1). When compounds can exist in multiple forms in nature like CO and CO2 you will preferably indicate it through the nomenclature, calling one a monoxide and the other a dioxide.

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What are the types of ions and how are they formed?
FromTheMoon [43]

Answer:

-Cations: They are formed by an atom losing an electron or electrons.

-Anions: They are formed by an atom gaining an electron or electrons.

5 0
3 years ago
Which list of elements from Group 2 on the Periodic Table is arranged in order of increasing atomic radius?
IgorC [24]
The correct answer is option 1. Be, Mg, and Ca is the correct order arranged in increasing atomic radius. This is predicted based on the periodic table. The atomic sizes increases as one moves downwards in the periodic table.
4 0
3 years ago
A solid powder is known to be a mixture of NaCl and Na2CO3, but the relative amounts of each compound in the sample are unknown.
AveGali [126]

Answer:

Concentration of sodium carbonate in the solution before the addition of HCl is 0.004881 mol/L.

Explanation:

Na_2CO_3(aq) +2 HCl(aq)\rightarrow 2NaCl(aq) + H_2O(l)+CO_2(g)

Molarity of HCl solution = 0.1174 M

Volume of HCl solution = 83.15 mL = 0.08315 L

Moles of HCl = n

molarity=\frac{moles}{Volume (L)}

0.1174 M=\frac{n}{0.08315 L}

n=0.1174 M\times 0.08315 L=0.009762 mol

According to reaction , 2 moles of HCl reacts with 1 mole of sodium carbonate.

Then 0.009762 mol of HCl will recat with:

\frac{1}{2}\times 0.009762 mol=0.004881 mol

Moles of Sodium carbonate = 0.004881 mol

Volume of the sodium carbonate containing solution taken = 1L

Concentration of sodium carbonate in the solution before the addition of HCl:

[Na_2CO_3]=\frac{0.004881 mol}{1 L}=0.004881 mol/L

4 0
3 years ago
Atomic mass is typically expressed in
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Answer:

amu

Explanation:

Please mark as brainleist

8 0
2 years ago
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leonid [27]

Answer:

Solution A is correct.

Explanation:

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3 years ago
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