Answer:
Total resistance is 19.6 Ω for the circuit .
Explanation:
Given:
Six resistors of a circuit namely
to
.
Where
and
are in series.
and
are in parallel.
and
are in parallel.
We know that continuous resistor which are in series are added up to find the equivalent resistance.
Similarly resistors which are arranged in parallel their equivalent resistance is
for the case of
and
.
According to the question:
Total resistance = R(equivalent) :
⇒ 
⇒ 
⇒ 
⇒ 
⇒
Ω
So the total resistance of the circuit depicted is 19.58 Ω approximated to nearest tenth that is 19.6 Ω
Resistance = voltage / current.
That's. 120v / 14A = 8.57 ohms.
By the way, voltage doesn't "run through" anything. Current does. That would be the 14 Amps.