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GrogVix [38]
2 years ago
15

Solve pls brainliest

Chemistry
1 answer:
inna [77]2 years ago
7 0

Answer:

Explanation:

The two green substances are not the same.  Most of their properties are different, except some are alike.  Since not all of their properties are matching, they are not the same substance.

I am not sure if this is what you were looking for, but if it is then I am happy to help.  

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A 1.00 L flask is filled with 1.15 g of argon at 25 ∘C. A sample of ethane vapor is added to the same flask until the total pres
tatiyna

Answer:

The partial pressure of argon in the flask = 71.326 K pa

Explanation:

Volume off the flask = 0.001 m^{3}

Mass of the gas = 1.15 gm = 0.00115 kg

Temperature = 25 ° c = 298 K

Gas constant for Argon R = 208.13 \frac{J}{kg k}

From ideal gas equation P V = m RT

⇒ P = \frac{m R T}{V}

Put all the values in above formula we get

⇒ P = \frac{0.00115}{0.001} × 208.13 × 298

⇒ P = 71.326 K pa

Therefore, the partial pressure of argon in the flask = 71.326 K pa

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