Answer:
Rb2CO3(aq)+Fe(C2H3O2)2(aq)--> 2Rb(C2H3O2)(aq) + FeCO3(s)
Explanation:
The reaction shown in the answer is the reaction of rubidium carbonate and iron II acetate. Rubidium is far more reducing than Fe II hence it can displace Fe II from its salt as shown.
The reducing property of metals depends on the value of their individual electrode potential values. For rubidium, its standard reduction potential is -2.98 V while that of Fe II is -0.44V. Hence rubidium can displace Fe II from its salt as shown above.
An ion-dipole interaction is the result of an electrostatic interaction between a charged ion and a molecule that has a dipole. It is an attractive force that is commonly found in solutions, especially ionic compounds dissolved in polar liquids. A cation can attract the partially negative end of a neutral polar molecule, while an anion attracts the positive end of a polar molecule. Ion-dipole attractions become stronger as the charge on the ion increases or as the magnitude of the dipole of the polar molecule increases.
This force of attraction is between an ion and a charge , it is weaker force than covalent bond and ionic bond . EX - The ion dipole interaction takes place between water and sodium ion , in it there is a small charge on oxygen molecule in water which is attracted by sodium charge .
Most commonly found in solutions. Especially important for solutions of ionic compounds in polar liquids.
A positive ion (cation) attracts the partially negative end of a neutral polar molecule.
to learn more about dipole interactions:-
https://brainly.in/question/1157107
Answer:
no the answer is oxidation
