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elena-14-01-66 [18.8K]
3 years ago
12

Please help asap that last part that’s blank

Chemistry
1 answer:
agasfer [191]3 years ago
3 0
0.315 cm3
Tell me if I'm wrong because I'm kind of bad at chemistry
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What is 2.75 mol of O2
ANTONII [103]

Answer:

2,75 mol of O2 it's 88 g of O2.

Explanation:

The weight of the diatomic molecule O2 is 32 g/mol. So considering that, you should multiply 2,75 mol · 32 = 88g :)

3 0
3 years ago
Define shielding and effective nuclear charge. What is the connection between the two?
ivolga24 [154]

Answer:

The relation between the shielding and effective nuclear charge is given as

Z_{eff} = Z -S

where s denote shielding

z_{eff} denote effective nuclear charge

Z - atomic number

Explanation:

shielding is referred to as the repulsion of an outermost electron to the pull of electron from valence shell.  Higher the electron in valence shell higher will be the shielding effects.  

Effective nuclear charge is the amount of net positive charge that valence electron has.

The relation between the shielding and the effective nuclear charge is given as  

Z_{eff} = Z -S

wheres denote shielding

z_{eff} denote effective nuclear charge  

Z - atomic number

8 0
3 years ago
Which of the following experiments would best test viscosity?
Juli2301 [7.4K]
C. pouring honey on a plate so the density of thickness and stickyness would 
be the highest
4 0
3 years ago
Which is a density independent factor limiting popultion growth
shusha [124]

The amount the amount of space a population has to grow in would be a limiting factor.


3 0
3 years ago
When 16.0 g of an unknown compound (a nonelectrolyte) are dis solved in exactly 800. g of water, the solution has a freezing poi
dexar [7]

Answer:

A. 266g/mol

Explanation:

A colligative property of matter is freezing point depression. The formula is:

ΔT = i×Kf×m <em>(1)</em>

Where:

ΔT is change in temperature (0°C - -0,14°C = 0,14°C)i is Van't Hoff factor (1 for a nonelectrolyte dissolved in water), kf is freezing point molar constant of solvent (1,86°Cm⁻¹) and m is molality of the solution (moles of solute per kg of solution). The mass of the solution is 816,0g

Replacing in (1):

0,14°C = 1×1,86°Cm⁻¹× mol Solute / 0,816kg

<em>0,0614 = mol of solute</em>.

As molar mass is defined as grams per mole of substance and the compound weights 16,0g:

16,0g / 0,0614 mol = 261 g/mol ≈ <em>A. 266g/mol</em>

I hope it helps!

3 0
3 years ago
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