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2 years ago

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The mass of an object is determined by: weighing the object with a scale multiplying the height, width, and length measuring the

object with an equal-arm balance using the water displacement method

1 answer:

rosijanka [135]2 years ago

7 0

The true scientific way is the last: using the water displacement method

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The surface charge density on an infinite charged plane is - 2.10 ×10−6C/m2. A proton is shot straight away from the plane at 2.

inn [45]

Explanation:

Formula to calculate electric field because of the plate is as follows.

E = $\frac{\sigma}{2 \times \epsilon_{o}}$

= $\frac{2.10 \times 10^{-6}}{2 \times 8.85 \times 10^{-12}}$

= $1.18 \times 10^{5} N/C$

Now, we will consider that equilibrium of forces are present there. So,

ma = qE

a = $\frac{1.6 \times 10^{-19} \times 1.18 \times 10^{5}}{1.67 \times 10^{-27}}$

= $1.13 \times 10^{13} m/s^2$

According to the third equation of motion,

$v^{2} = 2 \times a \times d$

or, d = $\frac{v^{2}}{2d}$

= $\frac{(2.4 \times 10^{6})^{2}}{2 \times 1.13 \times 10^{13}}$

= 0.254 m

Thus, we can conclude that the proton will travel 0.254 m before reaching its turning point.

7 0

2 years ago

You have two square metal plates with side lengths of (6.50 C) cm. You want to make a parallel-plate capacitor that will hold a

gtnhenbr [62]

Answer:

The necessary separation between the two parallel plates is 0.104 mm

Explanation:

Given;

length of each side of the square plate, L = 6.5 cm = 0.065 m

charge on each plate, Q = 12.5 nC

potential difference across the plates, V = 34.8 V

Potential difference across parallel plates is given as;

$V = \frac{Qd}{L^2 \epsilon_o} \\\\d = \frac{V L^2 \epsilon_o}{Q}$

Where;

d is the separation or distance between the two parallel plates;

$d = \frac{VL^2 \epsilon_o}{Q} \\\\d = \frac{34.8*(0.065)^2 *8.854*10^{-12}}{12.5*10^{-9}} \\\\d = 0.000104 \ m\\\\d = 0.104 \ mm$

Therefore, the necessary separation between the two parallel plates is 0.104 mm

6 0

3 years ago

If two objects of unequal mass collide, both objects will continue to move in the direction of

gayaneshka [121]

Assuming this is an elastic collision, they go in the direction of the object with more mass

3 0

3 years ago

Read 2 more answers

The "Garbage Project" at the University of Arizona reports that the amount of paper discarded by households per week is normally

Lorico [155]

Answer:

54%

Explanation:

We are given that

S.D=4.2 lb

Mean= $\mu=9.4 lb$

We have to find the percentage of household throw out at least 9 lb of paper a week.

Normal distribution formula :

$P(X\geq a)=P(z\geq \frac{a-\mu}{\sigma})$

We have a=9

$P(X\geq 9)=P(z\geq \frac{9-9.4}{4.2})=P(z\geq -0.1)$

$P(X\geq 9)=1-P(z$

$P(X\geq 9)=1-0.4602=0.5398\times 100=54$ %

Hence, the percentage of household throw out at least of paper a week=54%

7 0

2 years ago

When power and current are known use R = P/I^2 to calculate the resistance.

inna [77]

<h2> $\bf{ \underline{Given:- }}$ </h2>

$\sf• \: Power \:( P) = 300 \: watts$

$\sf• \: Current \: (I) = 30 \: amps$

$\\$

<h2> $\bf{ \underline{To \: Find:- }}$ </h2>

$\sf• \: The \: Resistance$

$\\$

$\huge\bf{ \underline{Solution :-:- }}$

$\bf \red {\bigstar{ Formula \: of \: Power \: (P) = \frac{ {I}^{2} }{R}}}$

$\sf \rightarrow 300= \frac{ {30}^{2} }{ R}$

$\sf \rightarrow 300 = \frac{900}{ R}$

$\rightarrow \sf R = \frac{300}{900}$

$\rightarrow \sf R = \frac{1}{3}$

$\rightarrow \sf R = 0.33$

$\bf \purple{Hence, \: the \: resistance \: is \: 0.33 \: Ω \: . }$

7 0

2 years ago