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3 years ago

What is the magnitude of the relativistic momentum of a proton with a relativistic total energy of 2.7 3 10210 j?

1 answer:

8 0

The equation that is applicable to this problem is expressed as 

p = γmu

where p is the relativistic momentum, m is equal to the proton mass and u is the speed of proton. γ is equal to 1/√(1 - u²/c²) where c is the speed of light.

Another equation to determine p fully is to use this relativistic equation:
E = γmc²

where E is the total kinetic energy including the gamma energy.

We are given with E = 2.7 × 10^(-10) J and from a proton’s data, mc^2 = 938.27201 MeV. Using the conversion from MeV to J which is 1 eV = 1.60218 * 10^(-19) J, we compute for γ

γ=E/mc^2 =2.7 × 10^(-10) J / 938.27201x10^6 eV *(1.60218 * 10^(-19) J/eV) = 1.80

we use this number to determine u from the second equation γ = 1/√(1 - u²/c²)

we square both sides and cross multiply, resulting to 
γ² (1 - u²/c²) = 1

u²/c² = (γ² -1)/γ²

u = c/y sq rt of (γ² -1)

u = 0.83

Substituting eventually to the first equation, we get

p = γmu

p = 1.80 * 1.67262 * 10^(-27) kg * 0.83 * 2.99792 * 10^8 m/s

p = 7.481 * 10^(-19) kg.m/s

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A ball rolls up a ramp with a velocity of 8.0 m/s. How high up the ramp does it travel?

Flura [38]

The greatest height the ball will attain is 3.27 m

<h3>Data obtained from the question</h3>

Initial velocity (u) = 8 m/s

Final velocity (v) = 0 m/s (at maximum height)

Acceleration due to gravity (g) = 9.8 m/s²

Maximum height (h) =?

The maximum height to which the ball can attain can be obtained as follow:

v² = u² – 2gh (since the ball is going against gravity)

0² = 8² – (2 × 9.8 × h)

0 = 64 – 19.6h

Collect like terms

0 – 64 = –19.6h

–64 = –19.6h

Divide both side by –19.6

h = –64 / –19.6h

h = 3.27 m

Thus, the greatest height the ball can attain is 3.27 m

Learn more about motion under gravity:

brainly.com/question/13914606

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2 years ago

A machinist turns the power on to a grinding wheel, which is at rest at time t = 0.00 s. The wheel accelerates uniformly for 10

sashaice [31]

Answer:

Time interval;Δt ≈ 37 seconds

Explanation:

We are given;

Angular deceleration;α = -1.6 rad/s²

Initial angular velocity;ω_i = 59 rad/s

Final angular velocity;ω_f = 0 rad/s

Now, the formula to calculate the acceleration would be gotten from;

α = Change in angular velocity/time interval

Thus; α = Δω/Δt = (ω_f - ω_i)/Δt

So, α = (ω_f - ω_i)/Δt

Making Δt the subject, we have;

Δt = (ω_f - ω_i)/α

Plugging in the relevant values to obtain;

Δt = (0 - 59)/(-1.6)

Δt = -59/-1.6

Δt = 36.875 seconds ≈ 37 seconds

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3 years ago

How do creepers explode

Nataliya [291]

Answer:

From you getting close to them

Explanation:

Because its big brain time.

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2 years ago

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A student claims that the Chernobyl accident proves that nuclear power is on safe for use in the United States which statement i

Setler79 [48]

Hi! Check out my valid counter argument below!

"The accident only released harmless gamma rays."

Hope I helped!

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3 years ago

Three masses are located in the x- y plane as follows: a mass of 6 kg is at (0 m, 0 m), a mass of 4 kg is at (3 m, 0 m), and a m

enot [183]

Answer:

The center of mass of three mass in the x-y plane is located at (1,0.5).

Explanation:

It is given that, a mass of 6 kg is at (0,0), a mass of 4 kg is at (3,0), and a mass of 2 kg is at (0,3). We need to find the center of mass of the system. Center of mass in x direction is :

$C_x=\dfrac{6\times 0+4\times 3+2\times 0}{6+4+2}\\\\C_x=1$

The center of mass in y direction is :

$C_y=\dfrac{6\times 0+4\times 0+2\times 3}{6+4+2}\\\\C_y=0.5$

So, the center of mass of three mass in the x-y plane is located at (1,0.5).

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3 years ago