<h3><em><u>therefore</u></em><em><u> </u></em><em><u>mass </u></em><em><u>m1=</u></em><em><u>4</u></em><em><u>.</u></em><em><u>8</u></em><em><u> </u></em><em><u>kg </u></em><em><u>and </u></em><em><u>the </u></em><em><u>tension</u></em><em><u> </u></em></h3><h3><em><u>in </u></em><em><u>the </u></em><em><u>horizontal</u></em><em><u> </u></em><em><u>spring </u></em><em><u>T2=</u></em><em><u>1</u></em><em><u>0</u></em><em><u>N</u></em><em><u>.</u></em></h3>
<h2><em><u>HOPE</u></em><em><u> </u></em><em><u>IT</u></em><em><u> HELPS</u></em><em><u> YOU</u></em><em><u> </u></em></h2>
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The momentum is equal for both. So
M(gun) * V(gun) = M(bullet) * V(bullet)
So
V(gun)=M(bullet) / M(gun) * V(bullet)
= .01 / 40 * 400 = 1/10 m/s = 0.1 m/s
A 1 m (39 inch) barrel length implies an acceleration of 80,000 m/s2
D=V^2 / (2*a) → a = V^2 / (2*D)
= 160,000 / 2 = 80,000 m/s2
V = a*t → t = V / a
= 400 / 80,000 = 1 / 200 second = 0.005 s
This means the gun is accelerated at
V = a * t → a = V / t
= 0.1 / 0.005 = 20 m/s2
And is displaced by
D = 1/2 * a * t^2 = 0.5 * 20 * 0.005^2
= 0.00025 m = 0.25 mm
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Related Questions (More Answers Below)
<u>Answer:</u>
The velocity of the truck is 34 m/s.
<u>Explanation:</u>
The momentum (p) of an object is the product of its mass (m) and its velocity (v) which can be written as:
<em>p = mv</em>
Here in this problem, we are given a truck which has a momentum of 40120 kg and a mass of 1180 kg and we are to find its velocity.
So substituting the given values in the above formula to find the velocity of the truck.
Truck's velocity = = 34 m/s.
Atom* the particles are (Electrons)
Answer:
v=13.4 m/s
Explanation:
The centripetal acceleration the car experiments is due to friction, so what we need is to write our equation using the maximum static friction, which is the case on the verge of sliding:
Which means (since we are in a horizontal surface):
So the maximum speed before sliding is:
Which for our values is: