What happens when two hydrogen atoms enter the ETS as part of either NADH or FADH2? Two hydrogen and one oxygen react to form a
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pH is the hydrogen ion concentration and pOH is the hydroxide ion concentration in the solution. pH KOH is 12.73, pOH KOH is 2.24 and pH NaCl is 7.
<h3>What are pH and pOH?</h3>pH is the negative log of the hydrogen ion concentration and pOH is the negative log of the hydroxide ion concentration.
The relation between the pH and pOH can be given as,
The pH of KOH can be calculated by the formula,
In the first case, the concentration of the KOH is
Substituting values in the equation:
Hence, the pH of KOH is 12.73.
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pOH of KOH can be calculated by the formula,
The hydroxide concentration of the KOH solution is
Substituting value in the equation:
Hence, the pOH of KOH is 2.24
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The pH of NaCl can be calculated by the formula,
In the third case, the concentration of the NaCl is
Substituting values in the equation:
Hence, the pH of KOH is 7.0.
Therefore, KOH is basic and NaCl is approximately neutral.
Learn more about pH and pOH here:
The amount of heat required to convert H₂O to steam is : 382.62 kJ
<u>Given data :</u>
Mass of liquid water ( m ) = 150 g
Temperature of liquid water = 43.5°C
Temperature of steam = 130°C
<h3 /><h3>Determine the amount of heat required </h3>The amount of heat required = ∑ q1 + q2 + q3 ----- ( 1 )
where ;
q1 = heat required to change Temperature of water from 43.5°C to 100°C . q2 = heat required to change liquid water at 100°C to steam at 100°C
q3 = heat required to change temperature of steam at 100°C to 130°C
- For q1
M* S*ΔT
= 150 * 4.18 * ( 100 - 43.5 )
= 35425.5 J
- For q2
moles * ΔHvap
= (150 / 18 )* 40.67 * 1000
= 338916.67 J
- For q3
M * S * ΔT
= 150 * 1.84 * ( 130 -100 )
= 8280 J
Back to equation ( 1 )
Amount of heat required = 35425.5 + 338916.67 + 8280 = 382622.17 J
≈ 382.62 kJ
Hence we can conclude that The amount of heat required to convert H₂O to steam is : 382.62 kJ.
Learn more about Specific heat of water : brainly.com/question/16559442