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DIA [1.3K]
3 years ago
14

Base course aggregate has a target dry density of 119.7 lb/cu ft in place. It will be laid down and compacted in a rectangular s

treet repair area of 2000 ft * 48 ft * 6 in. The aggregate in the stockpile contains 3.1% moisture. If the required compaction is 95% of the target, how many tons of aggregate will be needed?
Engineering
1 answer:
natita [175]3 years ago
5 0

Answer:

total weight of aggregate =  5627528 lbs = 2814 tons  

Explanation:

given data

dry density = 119.7 lb/cu ft

area = 2000 ft × 48 ft × 6 in

aggregate = 3.1%

required compaction = 95%

solution

we get  here volume of space to be filled with aggregate that is

volume = 2000 × 48 × 0.5 = 48000 ft³

when here space fill with aggregate of density is

density = 0.95 × 119.7    = 113.72 lb/ft³

and

dry weight of this aggregate will be  is

dry weight = 48000 × 113.72 = 5458320 lbs

and

we consider take percent moisture by weigh so that there weight of moisture in aggregate is express as

weight of moisture = 0.031 × 5458320 = 169208 lbs

and

total weight of aggregate will be

total weight of aggregate = 5458320 + 169208

total weight of aggregate =  5627528 lbs = 2814 tons  

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pochemuha

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7 0
3 years ago
Calculate the radius of gyration for a bar of rectangular cross section with thickness t and width w for bending in the directio
SVEN [57.7K]

Answer:

a)R= sqrt( wt³/12wt)

b)R=sqrt(tw³/12wt)

c)R= sqrt ( wt³/12xcos45xwt)

Explanation:

Thickness = t

Width = w

Length od diagonal =sqrt (t² +w²)

Area of raectangle = A= tW

Radius of gyration= r= sqrt( I/A)

a)

Moment of inertia in the direction of thickness I = w t³/12

R= sqrt( wt³/12wt)

b)

Moment of inertia in the direction of width I = t w³/12

R=sqrt(tw³/12wt)

c)

Moment of inertia in the direction of diagonal I= (w t³/12)cos 45=( wt³/12)x 1/sqrt (2)

R= sqrt ( wt³/12xcos45xwt)

4 0
4 years ago
You have the assignment of designing color codes for different parts. Three colors are used on each part, but a combination of t
Masja [62]

Answer:

7 available

Explanation:

Since 3 colors are available r = 3

Total combination = 35

nCr = 35 ---1

nCr = n!/(n-r)!r!---2

We put equation 1 and 2 together

n-1)(n-2)(n-3)!/n-3)! = 35x 3!

We cancel out (n-3)!

(n-1)(n-2) = 210

7x6x5 = 210

nC3 = 35

7C3 = 35

So If there are 35 combinations, 7 colors are available.

Thank you!

3 0
3 years ago
Discuss the trends in reaction forces versus jet velocity. Is the trend consistent with the theory? Does it make sense?
beks73 [17]

Answer:

The rate of fluid motion(Jet Velocity) exert a force on the object in contact with it. This force is also knowns as reactions forces.

In theory, this is related to Newton Second of motion which States that:

The rate of change of momentum is directly proportional to impressed force.

This makes sense and it is consistent with theory. Detailed explanation below:

Explanation:

A jet which can be illustrated as a moving fluid, in natural or artificial systems, may exert forces on objects in contact with it.

To analyze fluid motion, a finite region of the fluid (control volume) is usually selected, and the gross effects of the flow, such as its force or torque on an object, is determined by calculating the net mass rate that flows into and out of the control volume.

These forces can be determined, as in solid mechanics, by the use of Newton’s second law, or by the momentum equation(Consistent with the theory). The force exerted by a jet of fluid on a flat or curve surface can be resolved by applying the momentum equation. The study of these forces is essential to the study of fluid mechanics and hydraulic machinery.

In practice, Engineers and designers use the momentum equation to accurately calculate the force that moving fluid may exert on a solid body. For example, in hydropower plants, turbines are utilized to generate electricity. Turbines rotate due to force exerted by one or more water jets that are directed tangentially onto the turbine’s vanes or buckets. The impact of the water on the vanes generates a torque on the wheel, causing it to rotate and to generate electricity.

8 0
3 years ago
The volume fraction of particles in a WC-particle Cu-matrix CERMET is 0.84 Calculate the minimum expected elastic modulus, in GP
Lynna [10]

Answer:

the minimum expected elastic modulus is 372.27 Gpa

Explanation:

First we put down the data in the given question;

Volume fraction V_f = 0.84

Volume fraction of matrix material V_m = 1 - 0.84 = 0.16

Elastic module of particle E_f = 682 GPa

Elastic module of matrix material E_m = 110 GPa

Now, the minimum expected elastic modulus will be;

E_{CT = (E_f × E_m ) / ( E_fV_m  + E_m V_f  )

so we substitute in our values

E_{CT = (682 × 110 ) / ( [ 682 × 0.16 ]  + [ 110 × 0.84] )

E_{CT = ( 75,020 ) / ( 109.12 + 92.4 )

E_{CT = 75,020 / 201.52

E_{CT = 372.27 Gpa

Therefore, the minimum expected elastic modulus is 372.27 Gpa

7 0
3 years ago
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