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mash [69]
3 years ago
13

it creates parts from thin plastic sheets as opposed to plastic pellets. is it 1. Pickling 2. Thermoforming 3. Extrusion​

Engineering
2 answers:
iVinArrow [24]3 years ago
4 0

Answer:

thermoforming

Explanation:

please mark this answer as the brainlest

Sophie [7]3 years ago
4 0
I would say it’s option 2.

Hope this helped and have a nice day :)
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Ignoring any losses, estimate how much energy (in units of Btu) is required to raise the temperature of water in a 90-gallon hot
Rudik [331]

Answer:

Q=36444.11 Btu

Explanation:

Given that

Initial temperature = 60° F

Final temperature = 110° F

Specific heat of water = 0.999 Btu/lbm.R

Volume of water = 90 gallon

Mass = Volume x density

1\ gallon = 0.13ft^3

Mass ,m= 90 x 0.13 x 62.36 lbm

m=729.62 lbm

We know that sensible heat given as

Q= m Cp ΔT

Now by putting the values

Q= 729.62 x 0.999 x (110-60) Btu

Q=36444.11 Btu

5 0
3 years ago
An Ideal gas is being heated in a circular duct as while flowing over an electric heater of 130 kW. The diameter of duct is 500
max2010maxim [7]

Answer: The exit temperature of the gas in deg C is 32^{o}C.

Explanation:

The given data is as follows.

C_{p} = 1000 J/kg K,   R = 500 J/kg K = 0.5 kJ/kg K (as 1 kJ = 1000 J)

P_{1} = 100 kPa,     V_{1} = 15 m^{3}/s

T_{1} = 27^{o}C = (27 + 273) K = 300 K

We know that for an ideal gas the mass flow rate will be calculated as follows.

     P_{1}V_{1} = mRT_{1}

or,         m = \frac{P_{1}V_{1}}{RT_{1}}

                = \frac{100 \times 15}{0.5 \times 300}

                = 10 kg/s

Now, according to the steady flow energy equation:

mh_{1} + Q = mh_{2} + W

h_{1} + \frac{Q}{m} = h_{2} + \frac{W}{m}

C_{p}T_{1} - \frac{80}{10} = C_{p}T_{2} - \frac{130}{10}

(T_{2} - T_{1})C_{p} = \frac{130 - 80}{10}

(T_{2} - T_{1}) = 5 K

T_{2} = 5 K + 300 K

T_{2} = 305 K

           = (305 K - 273 K)

           = 32^{o}C

Therefore, we can conclude that the exit temperature of the gas in deg C is 32^{o}C.

7 0
3 years ago
Ruler game, HELPPPPP
viktelen [127]
D! :D
Hope I helped!!
3 0
2 years ago
Read 2 more answers
PLEASEE HELP.!! ILL GIVE BRAINLIEST.!! *EXTRA POINTS* DONT SKIP:((
Trava [24]

Answer:

16

Explanation:

Have a good day my friend

8 0
3 years ago
Read 2 more answers
A tank contains initially 2500 liters of 50% solution. Water enters the tank at the rate of 25 iters per minute and the solution
sergejj [24]

Answer:

Percentage of solution=32. 96%

Explanation:

Given that initially tank have 50% solution.It means that amount of solution=0.5 x 2500 =1250 lts

Lets take the amount of solution at time t = A

So

\dfrac{dA}{dt}=rate\ in\ solution -rate\ out\ solution

\dfrac{dA}{dt}=concentration\times rate\ in\ of\ water -concentration\times rate\ out\ of\ water

\dfrac{dA}{dt}=0\times 25-\dfrac{A}{2500}\times 50

\dfrac{dA}{dt}=-\dfrac{A}{50}

Now by integration

\ln A=-\dfrac{1}{50}t+C

Where C is the constant

Given that at t=0 ,A=1250

So C=\ln 1250

\ln A=-\dfrac{1}{50}t+\ln 1250

When t=20 min

\ln A=-\dfrac{1}{50}\times 20+\ln 1250

A=837.90

So percentage of solution after 20 min

=\dfrac{1250-837.9}{1250}\times 100

Percentage of solution=32. 96%

4 0
3 years ago
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