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grigory [225]
3 years ago
10

What is the only thing that cáue a change in QD?

Engineering
1 answer:
leonid [27]3 years ago
8 0

Answer:

This change in quantity demanded is caused by a change in the demand price. It is illustrated by a movement along a given demand curve. In fact, the only way to induce a change in quantity demanded is with a change in the price.

Explanation:

You might be interested in
1. A cylindrical casting is 0.3 m in diameter and 0.5 m in length. Another casting has the same metal is rectangular in cross-se
Lorico [155]

Based on the Chvorinov's rule, the diference in the <em>solidification</em> times of the two castings is 14.092 times the <em>solidification</em> time of the prism casting.

<h3>How to apply the Chvorinov's rule for casting processes</h3>

The Chvorinov's rule is an empirical method to estimate the cooling time of a casting in terms of a <em>reference</em> time. This rule states that cooling time (<em>t</em>) is directly proportional to the square of the volume (<em>V</em>), in cubic meters, divided to the surface area (<em>A</em>), in square meters. Now we proceed to model each casting:

<h3>Cylindrical casting</h3>

t = C · [0.25π · D² · L/(0.5π · D² + π · D · L)]²

t = C · [0.25 · D · L/(0.5 · D + L)]²    (1)

<h3>Prism casting</h3>

t' = C · [3 · T² · L/(6 · T · L + 2 · T · L + 6 · T²)]²

t' = C · [3 · T · L/(8 · L + 6 · T)]²     (2)

<h3>Relationship between the cross sections of both castings</h3>

3 · T² = 0.25π · D²     (3)

Where:

  • <em>t</em> - Cooling time of the cylindrical casting, in time unit.
  • <em>t'</em> - Cooling time of the prism casting, in time unit.
  • <em>C</em> - Cooling factor, in time unit per square meter.
  • <em>D</em> - Diameter of the cylinder, in meters.
  • <em>L</em> - Length of the casting, in meters.
  • <em>T</em> - Width of the cross section of the prism casting, in meters.

If we know that <em>D =</em> <em>0.3 m</em>, then the thickness of the prism casting is:

T = \sqrt{\frac{\pi}{12} }\cdot D

<em>T ≈ 0.153 m</em>

<em />

And (1) and (2) simplified into these forms:

<h3>Cylindrical casting</h3>

t = C · {0.25π · (0.3 m) · (0.5 m)/[0.5 · (0.3 m) + 0.5 m]}²

t = 0.0329 · C     (1b)

<h3>Prism casting</h3>

t' = C · {3 · (0.153 m) · (0.5 m)/[8 · (0.5 m) + 6 · (0.153 m)]}²

t' = 0.00218 · C     (2b)

Lastly we find the <em>percentual</em> difference in the solidification times of the two castings by using the following expression:

<em>r = (</em>1 <em>- t'/t) ×</em> 100 %

<em>r = (</em>1 <em>-</em> 0.00218<em>/</em>0.0329<em>) ×</em> 100 %

<em>r =</em> 93.374 %

The <em>cooling</em> time of the <em>prism</em> casting is 6.626 % of the <em>solidification</em> time of the <em>cylindrical</em> casting. The diference in the <em>solidification</em> times of the two castings is 14.092 times the <em>solidification</em> time of the <em>prism</em> casting. \blacksquare

To learn more on solidification times, we kindly invite to check this verified question: brainly.com/question/13536247

3 0
3 years ago
a centrifugal pump delivers water at the rate of 50kg/is . the inlet and outlet pressure are 2 bar and 6.2 bar respectively. the
Monica [59]

Answer:

21.6 kw

Explanation:

Given data:

m = 50 kg/s

Inlet pressure (p1) = 2 bar

outlet pressure(p2) = 6.2 bar

suction ( h1 ) = -2.2 m

delivery ( h2 ) = 8.5 m

d1 = 200 mm = 0.2 m

d2 = 100 mm = 0.1 m

Vs of water = 0.001 m^3/kg

next we have to determine the Q value

Q = V*A

Q = 0.001 * 50 = 0.05 m^3/s

next we have to calculate the various V's

V1 = Q/A1 = \frac{0.05*4}{\pi *0.2^2}  = 1.59 m/s

V2 = Q/A2 = \frac{0.05*4}{\pi *0.1^2} = 6.37 m/s

Determine the capacity of the electric motor

attached below is the detailed solution

7 0
3 years ago
The air velocity in the duct of a heating system is to be measured by a Pitot-static probe inserted into the duct parallel to th
Ilia_Sergeevich [38]

Answer:

Flow velocity

50.48m/s

Pressure change at probe tip

1236.06Pa

Explanation:

Question is incomplete

The air velocity in the duct of a heating system is to be measured by a Pitot-static probe inserted into the duct parallel to the flow. If the differential height between the water columns connected to the two outlets of the probe is 0.126m, determine (a) the flow velocity and (b) the pressure rise at the tip of the probe. The air temperature and pressure in the duct are 352k and 98 kPa, respectively

solution

In this question, we are asked to calculate the flow velocity and the pressure rise at the tip of probe

please check attachment for complete solution and step by step explanation

8 0
3 years ago
Aiman is 80 inches tall. How tall is Aiman in centimeters? Show your work.
harkovskaia [24]
203.2 centimeters.
This is because 1 inch = 2.54 centimeters which means multiply 80 inches X 2.54 = 203.2 centimeters.
5 0
3 years ago
The town of Camp Verde has been directed to upgrade its primary WWTP to a secondary plant that can meet an effluent standard of
Artist 52 [7]

For efficient treatment, the dissolved oxygen concentration in the aeration tank must be kept between 1-3 mg/L. The microbial biomass will die at low DO levels, and it will take time and money to rebuild it.

The depth, which normally ranges from 3 to 4.5 meters, determines how effectively air is aerated. The breadth, which is typically maintained between 5 and 10 meters, regulates the mixing. The ideal width-to-depth ratio is 1.2 to 2.2. The distance shouldn't be shorter than 30 meters or longer than 100 meters. Bacteria used in wastewater treatment and stabilization are given oxygen by aeration. The bacteria require oxygen for biodegradation to take place.

Learn more about efficient here-

brainly.com/question/13154811

#SPJ4

4 0
1 year ago
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