Answer:
Plutonium, has formula Pu with molecular mass 94
Explanation:
Since its mass is 145 metric tons, the barge must displace 145 metric tons of water
in order to float. 145 metric tons= 145,000 kilograms. Use the rough-but-close rule
of thumb that 1 liter of water has 1 kilogram of mass. So the barge displaces 145,000
liters, which is also 145 cubic meters of water.
(Length) x (width) x (depth of the part under water) = 145 cubic meters
Draft of the barge (depth under water) = 145 / (50 x 20) = 145/70 = <em>2.07 meters</em>.
No, it will not clear the reef 1.5 meters below the surface. Either the barge will shave off the top 0.57 meter of the reef, or else the reef will do serious damage to the barge. In any case, there will be a situation.
Answer:
v = 0.667 m / s, m = 6746 kg
Explanation:
For this exercise we must use the relationship between work and kinetic energy
W = ΔK
the work is defined by
W = F. x
bold indicates vectors
W = F x cos θ
in this case the force is in the same direction of displacement
W = F x
F x = K_f - K₀
as the body starts from rest the initial kinetic energy is zero
F x = ½ m v²
Now let's use the relationship between momentum and momentum
I = Δp
I = F t
Δp = m v_f - m v₀
as part of rest v₀ = 0
F t = m v
Let's write our system of equations
F x = ½ m v²
F t = m v
we have a system of two equations with two unknowns, let's divide the two expressions
x / t = ½ v
v = 2x / t
v = 2 10/30
v = 0.667 m / s
we look for the mass
F t = m v
m = F t / v
m = 150 30 / 0.667
m = 6746 kg
140 ? i’m guessing there doesn’t look like there’s much to the question