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gulaghasi [49]
3 years ago
11

I would like to know why this is the correct answer

Physics
1 answer:
Helen [10]3 years ago
8 0

The acceleration of the object if the net force is decreased = 0.13 m/s²

<h3>Further explanation</h3>

Given

A net force of 0.8 N acting on a 1.5-kg mass.

The net force is decreased to 0.2 N

Required

The acceleration of the object if the net force is decreased

Solution

Newton's 2nd law :

\tt \sum F=m.a

The mass used in state 1 and 2 remains the same, at 1.5 kg

  • state 1

ΣF=0.8 N

m=1.5 kg

The acceleration, a:

\tt a=\dfrac{\sum F}{m}\\\\a=\dfrac{0.8}{1.5}\\\\a=0.53`m/s^2

  • state 2

ΣF=0.2 N

m=1.5 kg

The acceleration, a:

\tt a=\dfrac{\sum F}{m}\\\\a=\dfrac{0.2}{1.5}\\\\a=0.13~m/s^2

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Zina [86]
By definition we have to:
 LOG (k2 / k1)=(-Ea/R)*(1/T1-1/T2)
 Where,
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 T1 = 400.0 k
 T2 = 450.0 k
 R is the ideal gas constant
 R = 8.314 KJ / (Kmol * K)
 Substituting
 ln (0.0117/0.689)=-Ea/(8.314)*((1/400)-(1/450))
 Clearing Ea:
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 answer
<span> the activation energy in kilojoules for this reaction is
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7 0
3 years ago
Read 2 more answers
Determine the centripetal force on a vehicle rounding a circular curve with a radius of 80 m at a constant speed of 90 km/h if t
quester [9]
Mass of the vehicle = 2000 kg
Velocity of the vehicle = 90 km/hr
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Radius of the curve = 80 m
Then
Centripetal force = [2000 * (25)^2]/80
                            = (2000 * 625)/80
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I hope that this is the answer that you were looking for and the answer has come to your desired help. 
3 0
3 years ago
Can some help me out on some science ?
Dennis_Churaev [7]
Yea but whats the question
3 0
3 years ago
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Two students side in carts opposite to one another in a spinning Ferris wheel as shown.
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Net work done  on student B by the Ferris wheel in moving from the top to the bottom  is mathematically given as

net work done on A =0.

<h3>Net work done  </h3>

Generally the equation for the work energy theorem is mathematically given as

net work done on A = change in kinetic energy of A.

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change in kinetic energy = 0.

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brainly.com/question/756198

5 0
2 years ago
Cousin Throckmorton is playing with the clothesline. One end of the clothesline is attached to a vertical post. Throcky holds th
Oksi-84 [34.3K]

Answer:

The  frequencies are  f_n  =  n (0.875 )

Explanation:

From the question we are told that

   The speed of the wave is  v  =  0.700 \  m/s

   The  length of vibrating  clothesline is  L  =  40.0 \  cm = 0.4 \ m

Generally the fundamental frequency is  mathematically represented as

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=>     f =  \frac{ 0.700 }{2 *  0.4   }

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Now  this other frequencies of vibration experience by the clotheslines are know as harmonics and they are obtained by integer multiple of  the fundamental frequency

So  

   The  frequencies are mathematically represented as

       f_n  =  n  * f

=>     f_n  =  n (0.875 )

Where  n  =  1, 2, 3 ....

       

3 0
3 years ago
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