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Umnica [9.8K]
3 years ago
9

An object in motion stays in motion, in a _______________________, unless acted on by an external _____________________________

force.
Physics
1 answer:
AlekseyPX3 years ago
5 0

Answer:

An object in motion stays in motion, in a uniform motion, unless acted on by an external unbalanced force.

Explanation:

This statement is also known as Newton's First Law of motion (also called "Law of inertia").

It states that:

"When an object is in motion at constant velocity (or at rest), the object tends to remain in its state of motion at constant velocity (or at rest), unless there is a net external unbalanced force acting on it".

The action of an external unbalanced force would change the state of motion of the object; in particular, it will cause an acceleration in the object, according to Newton's Second Law of motion:

F=ma

where

F is the net force on the object

m is the mass of the object

a is its acceleration

Therefore, we can see that if the external force acting on the object is zero:

F = 0

Then the acceleration of the object is also zero:

a = 0

And so, the object will continue its motion with constant velocity (or it will remain at rest, if it was at rest).

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Two blocks can collide in a one-dimensional collision. The block on the left hass a mass of 0.40 kg and is initially moving to t
Dmitrij [34]

Answer:

The velocity of the first block is 1.15m/s while of the second block 2.56m/s.

Explanation:

Momentum is only conserved in an isolated system, and because this problem requires us to find the value of the two variables, we need two equations; therefore, to conserved momentum the energy must be released in to the system only after the collision has occurred.

Therefore, from conservation of momentum

m_1v_1= m_1v_{1f}+m_2v_{2f}

0.4(2.4)= 0.4v_{1f}+0.5v_{2f}

\boxed{\:0.96= 0.4v_{1f}+0.5v_{2f}}

and from conservation of energy

$\frac{1}{2}m_1v_1^2+1.2 = \frac{1}{2} m_1v_{1f}^2+\frac{1}{2}m_2v_{2f}^2  $

m_1v_1^2+2.4 =  m_1v_{1f}^2+m_2v_{2f}^2}

$\boxed{\:3.804=  0.4v_{1f}^2+0.5v_{2f}^2.}$

Thus, we have two equations and two unknowns

(1). \: 0.4v_{1f}+0.5v_{2f}=0.96

{(2). \:  0.4v_{1f}^2+0.5v_{2f}^2 =3.804

which has solutions

(v_{1f}, v_{2f}) = (1.15,2.56)

and

(v_{1f}, v_{2f}) = (1.15,-2.56)

Since the blocks cannot pass through each other, the 0.5kg block cannot have v_{2f} = -2.56m/s  (moves to the left) while the 0.4 kg block has v_{1f} = 1.15m/s (moves to the right); therefore, we take the first solution for the velocities:

(v_{1f}, v_{2f}) = (1.15,2.56).

Thus , the velocity of the first block is 1.15m/s while of the second block 2.56m/s.

5 0
3 years ago
Read 2 more answers
Physics help please
zhuklara [117]

Answer: 37.981 m/s

Explanation:

This situation is related to projectile motion or parabolic motion, in which the travel of the ball has two components: <u>x-component</u> and <u>y-component.</u> Being their main equations as follows:

<u>x-component: </u>

x=V_{o}cos\theta t   (1)

Where:

x=52 m is the point where the ball strikes ground horizontally

V_{o} is the ball's initial speed

\theta=0 because we are told the ball is thrown horizontally

t is the time since the ball is thrown until it hits the ground

<u>y-component: </u>

y=y_{o}+V_{o}sin\theta t+\frac{gt^{2}}{2}   (2)

Where:

y_{o}=120m  is the initial height of the ball

y=0  is the final height of the ball (when it finally hits the ground)

g=-9.8m/s^{2}  is the acceleration due gravity

Knowing this, let's start by finding t from (2):

<u></u>

0=y_{o}+V_{o}sin(0\°) t+\frac{gt^{2}}{2}   (3)

0=y_{o}+\frac{gt^{2}}{2}  

t=\sqrt{\frac{-2 y_{o}}{g}}   (4)

t=\sqrt{\frac{-2 (120 m)}{-9.8m/s^{2}}}   (5)

t=4.948 s   (6)

Then, we have to substitute (6) in (1):

x=V_{o}cos(0\°) t   (7)

And find V_{o}:

V_{o}=\frac{x}{t}   (8)

V_{o}=\frac{52 m}{4.948 s}   (9)

V_{o}=10.509 m/s   (10)

On the other hand, since we are dealing with constant acceleration (due gravity) we can use the following equation to find the value of the ball's final velocity V:

V=V_{o} + gt (11)

V=10.509 m/s + (-9.8 m/s^{2})(4.948 s) (12)

V=-37.981 m/s (13) This is the ball's final velocity, and the negative sign indicates its direction is downwards.

However, we were asked to find the <u>ball's final speed</u>, which is the module of the ball's final vleocity vector. This module is always positive, hence the speed of the ball just before it strikes the ground is 37.981 m/s (positive).

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What occurs when an object travels in a curved path
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There must be a centripetal force to move the object move in a curve path.
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3 years ago
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____________ showed that matter and energy are two forms of the same thing.
Darya [45]
Einstein. That genius
7 0
3 years ago
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If Earth were 10.0 times farther away from the Sun than it is now, how many times weaker would the gravitational force between t
choli [55]

If Earth were 10.0 times farther away from the Sun than it is now, 100 times weaker would the gravitational force between the Sun and Earth.

What is Gravitational Force?

According to Newton's universal law of gravitation, The force of attraction between any two bodies is directly proportional to the product of their masses and is inversely proportional to the square of the distance between them.

What causes gravitational force?

Earth's gravity comes from all its mass. All its mass makes a combined gravitational pull on all the mass in your body. That's what gives you weight. And if you were on a planet with less mass than Earth, you would weigh less than you do here.

Learn more about gravitational force:

brainly.com/question/862529

#SPJ4

5 0
2 years ago
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