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Anastasy [175]
3 years ago
6

For a cylinder of hydrogen (H2) gas, you have been informed that the rms speed of the molecules is 505 m/s. Determine the temper

ature of the gas in degrees K. Use 2.0159 ✕ 10−3 kg as the mass of a mole of hydrogen molecules.
Physics
1 answer:
Svet_ta [14]3 years ago
6 0

Answer:

20.6 K

Explanation:

The root mean square velocity is the square root of the average of the square of the velocity. It can be calculated using the following expression.

v_{rms}=\sqrt{\frac{3RT}{M} }

where,

v_{rms}: root mean square velocity

R: ideal gas constant

T: absolute temperature

M: molar mass

Then, we can find the temperature,

v_{rms}=\sqrt{\frac{3RT}{M} }\\T=\frac{v_{rms}^{2}M }{3R} =\frac{(505m/s)^{2}2.0159 \times 10^{-3} kg/mol}{3 \times (8.314 J/mol.K)} =20.6 K

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Options: A. Tech A. B. Tech B. C. Tech And B. C. None of the above.

Answer:Tech A and B

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3 years ago
What is the total amount of force needed to keep a 6.0 kg object moving at speed
DanielleElmas [232]

Answer:

C. 0 N

Explanation:

In the absence of external forces, a body in motion will stay in motion.

F = ma

F = 6.0(0) = 0

8 0
3 years ago
Read 2 more answers
Describe the quantum mechanical model of the atom and several observations which support this model.
PIT_PIT [208]

This means that we shouldn't imagine electrons as single objects going around the atom. Instead, all we know is the probability of finding an electron at a particular location. What we end up with is something called an electron cloud. An electron cloud is an area of space in which an electron is likely to be found. It's like a 3-D graph showing the probability of finding the electron at each location in space. Quantum mechanics also tells us that a particle has certain numbers (called quantum numbers) that represent its properties. Just like how materials can be hard or soft, shiny or dull, particles have numbers to describe the properties. These include a particle's orbital quantum numbers, magnetic quantum number, and its spin. No two electrons in an atom can have exactly the same quantum numbers. Orbital quantum numbers tell you what energy level the electron is in. In the Bohr model, this represents how high the orbit is above the nucleus; higher orbits have more energy. The first orbit is n=1, the second is n=2, and so on. The magnetic quantum number is just a number that represents which direction the electron is pointing. The other important quantum mechanical property, called spin, is related to the fact that electrons come in pairs. In each pair, one electron spins one way (with a spin of one half), and the other electron spins the other way (with a spin of negative one half). Two electrons with the same spin cannot exist as a pair. This might seem kind of random, but it has effects in terms of how magnetic material is. Materials that have unpaired electrons are more likely to be magnetic

7 0
3 years ago
A ball has a diameter of 3.79 cm and average density of 0.0838 g/cm3.
suter [353]

Answer: 0.258 N

Explanation:

As the density of the object is much less than the density of water, it’s clear that the buoyant force, is greater than the weight of the object, which means that in normal conditions, it would float in water.

So, in order to get the ball submerged in water, we need to add a downward force, that add to the weight, in order to compensate the buoyant force, as follows:

F = Fb – Fg

Fb= δH20* 4/3*π*(d/2)³  * g

Fg = δb* 4/3*π*(d/2)³ *g

F= (δH20- δb) * 4/3*π*(d/2)³*g

Replacing by the values of the densities, and the ball diameter, we finally get:

F= 0.258 N

3 0
3 years ago
Astronomers have observed a small, massive object at the center of our Milky Way Galaxy. A ring of material orbits this massive
Setler [38]

Answer:

The mass of the massive object at the center of the Milky Way galaxy is 3.44\times10^{37}\ Kg

Explanation:

Given that,

Diameter = 10 light year

Orbital speed = 180 km/s

Suppose determine the mass of the massive object at the center of the Milky Way galaxy.

Take the distance of one light year to be 9.461×10¹⁵ m. I was able to get this it is 4.26×10³⁷ kg.

We need to calculate the radius of the orbit

Using formula of radius

r=\dfrac{d}{2}

r=\dfrac{15\times9.461\times10^{15}}{2}

r=7.09\times10^{16}\ m

We need to calculate the mass of the massive object at the center of the Milky Way galaxy

Using formula of mass

M=\dfrac{v^2r}{G}

Put the value into the formula

M=\dfrac{(180\times10^3)^2\times7.09\times10^{16}}{6.67\times10^{-11}}

M=3.44\times10^{37}\ Kg

Hence, The mass of the massive object at the center of the Milky Way galaxy is 3.44\times10^{37}\ Kg

5 0
3 years ago
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