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IgorC [24]
3 years ago
12

Scientists study the life history of stars by examining what trait of stars? A. size B. energy output C. color D. all of these

Physics
1 answer:
erastovalidia [21]3 years ago
6 0

I'm gonna go at on a limb here and say all of these....

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A student is conducting a physics experiment and rolls four different-
joja [24]

Answer:

<em>I think the answer is C</em>

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Explanation:

Its heavy but not too heavy

4 0
3 years ago
Two electrons are separated by 1.70 nm. What is the magnitude of the electric force each electron exerts on the other?
lidiya [134]

Answer:

F=7.96*10^{-11}N

Explanation:

According to Coulomb's law, the magnitude of the electric force between two equals charges (q) is given by:

F=\frac{kq^2}{d^2}

Here k is the coulomb constant and d is the distance between the charges. For two electrons we have:

F=\frac{ke^2}{d^2}\\F=\frac{8.99*10^{9}\frac{N\cdot m^2}{C^2}(-1.6*10^{-19}C)^2}{(1.7*10^{-9}m)^2}\\F=7.96*10^{-11}N

8 0
3 years ago
How were the fossil symbols and mountain bets helpful in deciding where to move the continenets
Alborosie
<span>Similar fossils found on different continents helped geologists determine how the continents used to be connected. Mountain belts marked the boundaries of moving plates, which showed in which direction the different continents drifted. Extrapolating from this information, scientists had a rough idea of how the continents were arranged eons ago.</span>
6 0
3 years ago
A 0.25 kg ball is suspended from a light 0.65 m string as shown. The string makes an angle of 31° with the vertical. Let U = 0 w
steposvetlana [31]

Explanation:

a) The height of the ball h with respect to the reference line is

h = L - L\cos{31°} = L(1 - \cos{31°})

so its initial gravitational potential energy U_0 is

U = mgh = mgL(1 - \cos{31°})

\:\:\:\:\:=(0.25\:\text{kg})(9.8\:\text{m/s}^2)(0.65\:\text{m})(1 - \cos{31})

\:\:\:\:\:=0.23\:\text{J}

b) To find the speed of the ball at the reference point, let's use the conservation law of energy:

\Delta{K} + \Delta{U} = 0 \Rightarrow K_0 + U_0 = K + U

We know that the initial kinetic energy K_0, as well as its final gravitational potential energy U are zero so we can write the conservation law as

mgL(1 - \cos{31°}) = \frac{1}{2}mv^2

Note that the mass gets cancelled out and then we solve for the velocity v as

v = \sqrt{2gL(1 - \cos{31°})}

\:\:\:\:\:= \sqrt{2(9.8\:\text{m/s}^2)(0.65\:\text{m})(1 - \cos{31°})}

\:\:\:\:\:= 1.3\:\text{m/s}

5 0
3 years ago
Read 2 more answers
Describe how the rider exerts a force on the motorcycle
LUCKY_DIMON [66]
Well, one example is that the weight of the rider puts downward force on the motorcycle, which is absorbed by the suspension or shocks or something.
4 0
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