Answer:
On the exterior of the cell.
Explanation:
The black spots as mentioned in the given case would appear on the exterior of the cell after three hours, which suggests that the proteins or the enzymes had been discharged from the pancreatic cell. The mentioned method of labeling and then chasing the component is known as a pulse-chase experiment.
In this experiment, the labeled compounds are used to follow the dynamics of cellular pathways and procedures. The molecules in a cell get produced and degraded spontaneously at various rates. These changes in the localization of the molecule and its expression levels with time can be determined by exposing or pulsing cells to a labeled compound.
After this the cells are exposed sequentially to the same compound unlabeled, the process is termed as the chase. The compounds are generally labeled with fluorescent dyes or radioisotopes.
Trying to cheat on exam lol
but sorry if i get you wrong but possibly not
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C) The cell is in telophase II, and cytokinesis will occur next.</span>
All of the above i think.
Answer:
a) How many genotypes will occur in F2
--The genotypes would be- AA Aa aa BB Bb bb CC Cc cc DD Dd dd EE Ee ee (15 genotypes)
Reason-
This is because, after crossing the parents, the F1 generation would all be Heterozygous dominant since one parent is homozygous dominant, while the other is homozygous recessive.
b) 25% of all F2 genotypes would be recessive across the 5 loci
Reason-
This is because each loci would produce only a 25% chance for a recessive trait, which would results to a general probability of 25% also.
c) Yes i would change my answer in A and B if the parent cross was- AABBCCDDEE X aaBBccDDEE
d) Yes i would change my answer in A and B if the parent cross was- AABBCCDDEE X aabbccddEE
Answer:
They are 3 in numbers
Explanation:
which are the airway, the lungs, and the muscles of respiration
