Ask question

Ask question

All categories

3 years ago

10

How far away is the furthest artificial satellite orbiting earth?

1 answer:

rusak2 [61]3 years ago

8 0

Real-time distance and velocity data is provided by NASA and JPL. At a distance of 153.88 AU (23.020 billion km; 14.304 billion mi) from Earth as of September 5, 2021, it is the most distant artificial object from Earth. The probe made successful flybys of Jupiter, Saturn, and Saturn's largest moon, Titan.

You might be interested in

What will occur when two have reach one another

grigory [225]

Well, you would have to be more specific! Sorry I couldn't help you, but if you have the whole question and it is udnerstandable, please repost your question!

5 0

3 years ago

What is the average speed of an object with a total distance traveled of 45 meters in 50 seconds

Anettt [7]

Answer: 0.9m/s

Explanation:

Use equation for speed:

V=S/t

S-distance; S=45m

t-time; t=50 s

V=S/t

V=45m/50s

V=0.9 m/s

7 0

3 years ago

Giant cave systems have formed through the reaction of acids with the that make up limestone.

seraphim [82]

The answer is C. Carbonates

3 0

3 years ago

Read 2 more answers

A physics student stands on a cliff overlooking a lake and decides to throw a softball to her friends in the water below. She th

aliina [53]

Answer:

58.5 m

Explanation:

First of all, we need to find the total time the ball takes to reach the water. This can be done by looking at the vertical motion only.

The initial vertical velocity of the ball is

$u_y = u sin \theta$

where

u = 21.5 m/s is the initial speed

$\theta=33.5^{\circ}$ is the angle

Substituting,

$u_y = (21.5) sin 33.5^{\circ} =11.9 m/s$

The vertical position of the ball at time t is given by

$y = h + u_y t + \frac{1}{2}gt^2$

where

h = 13.5 m is the initial heigth

$g = -9.8 m/s^2$ is the acceleration of gravity (negative sign because it points downward)

The ball reaches the water when y = 0, so

$0 = h + u_yt +\frac{1}{2}gt^2\\0 = 13.5 +11.9 t - 4.9t^2$

Which gives two solutions: t = 3.27 s and t = -0.84 s. We discard the negative solution since it is meaningless.

The horizontal velocity of the ball is

$u_y = u cos \theta = (21.5) cos 33.5^{\circ} =17.9 m/s$

And since the motion along the horizontal direction is a uniform motion, we can find the horizontal distance travelled by the ball as follows:

$d= u_x t = (17.9)(3.27)=58.5 m$

3 0

3 years ago

Which of these is a good example of Newton's First Law of inertia

Andru [333]

Answer:

one body movement to the side when a car makes a sharp turn

3 0

3 years ago

Read 2 more answers