Answer:
i dont know ask the man behind the man
Explanation:
Answer:
CO.
Explanation:
Assuming the given percentages are by mass, we can solve this problem via imagining we have <em>100 g of the compound</em>, if that were the case we would have:
Now we <u>convert those masses into moles</u>, using the<em> elements' respective molar masses</em>:
- 42.9 g of C ÷ 12 g/mol = 3.57 mol C
- 57.1 g of O ÷ 16 g/mol = 3.58 mol O
As the number of C moles and O moles is roughly the same, the empirical formula for the compound is <em>CO</em>.
<h3>CHEMISTRY</h3>
What is the most basic aromatic amine’s common name?
a) Benzenamine
b) Benzylamine
c) Aniline
d) Aminobenzene
#BRAINLYEVERYDAY
Answer: Chemical X H3 and f1
Explanation:
Mass is equal to moles x molar mass, and the molar mass of C6H12 is 84, therefore the mass is 436.8 g, but 437 rounded to correct significant figures