The number of moles of oxygen required to completely react with 54 g of aluminum is 1.5 moles.
<h3>Number of moles of the reacting aluminum </h3>
moles = reacting mass/molar mass
moles = 54/27
moles = 2 moles
From the given reaction of oxygen and aluminum;
4Al + 30₂ → 2Al₂O₃
4 moles of Al ----------> 3 moles of oxygen
2 moles of AL --------> ? moles of oxygen
= (2 x 3)/4
= 1.5 moles
Thus, the number of moles of oxygen required to completely react with 54 g of aluminum is 1.5 moles.
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Number of neutrons = 8
<h3>Further explanation</h3>
Given
7 protons, 7 electrons, and a mass number of 15.
Required
Number of neutrons
Solution
Within the atom there are subparticles, namely protons, neutrons and electrons
Protons and neutrons are present in the atomic nucleus, while electrons surround the atomic nucleus in the atomic shell
Atomic number = number of protons = number of electrons
Mass number= number of protons + number of neutrons
15 = 7 + number of neutrons
number of neutrons = 8
Answer:
0.07975 M NaOH
Explanation:
First determine the molarity of your acid, KHP. Convert grams to moles using the MW given and then divide by the volume of water.
0.3175 g KHP • (1 mol KHP / 204.2 g KHP) = 0.001555 mol KHP
0.001555 mol KHP / 0.040 L = 0.03888 M KHP
The reaction between KHP and NaOH is one-to-one, so you can just use M1V1 = M2V2 to solve for M2 (the molarity of NaOH).
M1 = 0.03888 M KHP
V1 = 40 mL
M2 = ? M NaOH
V2 = 19.45 mL NaOH
(0.03888 M KHP)(40 mL) = M2(19.5 mL NaOH)
M2 = 0.07975 M NaOH
