Answer:
2H2S + 3O2 → 2SO2 + 2H2O
Explanation:
Step 1: Data given
Hydrogen sulfide = H2S
Oxygen = O2
sulfur dioxide = SO2
water = H2O
Step 2: The unbalanced equation
H2S + O2 → SO2 + H2O
Step 3: Balancing the equation
H2S + O2 → SO2 + H2O
On the left side we have 2x O (in O2) and on the right side we have 3x O (2x in SO2 and 1x in H2O). To balance the amount of O, we have to multiply O2 (on the left side) by 3 and SO2 and H2O on the right side by 3.
H2S + 3O2 → 2SO2 + 2H2O
On the right side we have 4x H and on the left side we have 2x H. To balance the amount of H, we have to multiply H2S by 2.
Now the equation is balanced.
2H2S + 3O2 → 2SO2 + 2H2O
Before you can identify how much you need, first you need to
solve and write the equation.
You need to know first that you need to convert grams of ZnO --> moles of ZnO
= 358.5 g ZnO x 1 mol ZnO / 81.39g ZnO
Solve and it will give you = 4.40 mol of ZnO
Next, multiply the answer above to 1 mol O2 / 2 mol ZnO
It will give you the answer of 2.20 mol of O2
Multiply the answer above to the molar mass. This will give
you the answer of what you’re looking for.
Molar mass: 32
= 2.20 mol O2 x 32g O2 / 1 mol O2
= 70.4g O2
The grams of O2 that are required to produce 385.5 grams of
zno is: 70.4 g O2
The 1 one electrons have positive charge
Hydrogen should be your final answer.
Answer : The enthalpy change is, 7.205 KJ
Solution :
The conversions involved in this process are :
Now we have to calculate the enthalpy change.
where,
= enthalpy change = ?
m = mass of water = 10 g
= specific heat of solid water = 2.09 J/gk
= specific heat of liquid water = 4.18 J/gk
n = number of moles of water =
= enthalpy change for fusion = 6.01 KJ/mole = 6010 J/mole
Now put all the given values in the above expression, we get
(1 KJ = 1000 J)
Therefore, the enthalpy change is, 7.205 KJ