We can determine the empirical formula by first converting each of the grams to moles. remember to do this, first, we need the molar mass of the molecules which can be calculated by adding the mass of the atoms from the periodic table.
molar mass of CO2= 44.0 g/mol
molar mass of H2O= 18.02 g/mol
now, lets determine the grams of each atom
Carbon: 23.98 g x (12.011 g / 44.01 g) = 6.54 g C
Hydrogen: 4.91 g x (2.0158 g / 18.02 g) = 0.55 g H
Oxygen: 10.0 - (6.54 + 0.55) = 2.91 g O
Now let's convert each mass to moles.
C: 6.54 g / 12.01 g / mol = 0.54 mol
H: 0.55 g / 1.01 g/mol = 0.54 mol
O: 2.91 g / 16.00 g/mol = 0.18 mol
now that we have the moles of each atom, we need to divide them by the smallest value to find the ration. If you do not get the whole number, you need to multiply until to get a whole number.
C: 0.54 mol / 0.18 mol = 3
H: 0.54 mol / 0.18 mol = 3
O: 0.18 mol / 0.18 mol = 1
empirical formula--> C₃H₃O
6 - one sodium atom, 1 hydrogen atom, 1 carbon atom, and 3 oxygen atoms.
The new pressure will be 7.65 atm
<h3>General gas law</h3>
The problem is solved using the general gas equation:
P1V1/T1 = P2V2/T2
In this case, P1 = 3.4 atm, V1 = 1500 mL, T1 = 25 
, V2 = 2000 mL, and T2 = 75
What we are looking for is P2.
Thus, P2 = P1V1T2/T1V2
= 3.4 x 1500 x 75/25 x 2000 = 382500/50000 = 7.65 atm
More on general gas laws can be found here: brainly.com/question/2542293
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The number of grams of NaCl required to make 150.0 ml of a 5.000m solution is 43.875 grams
<u><em>calculation</em></u>
Step 1: calculate moles of NaCl
moles= molarity x volume in liters
volume in liters = 150.0 ml/1000= 0.15 l
moles is= 5.000mol/l x0.15 l =0.75 moles
Step2 : find mass
mass= moles x molar mass
molar mass of NaCl= 23 +35.5 = 58.5 g/mol
mass= 0.75 moles x58.5 g/mol = 43.875 grams
