<u>Answer:</u> The formula of the compound formed between rubidium and fluorine is RbF
<u>Explanation:</u>
Ionic bond is defined as the bond which is formed by complete transfer of electrons from one atom to another atom.
The atom which looses the electron is known as electropositive atom and the atom which gains the electron is known as electronegative atom. This bond is usually formed between a metal and a non-metal.
Rubidium is the 37th element of the periodic table having electronic configuration of 
This will loose 1 electron to form 
ion
Fluoride is the 9th element of the periodic table having electronic configuration of 
This will gain 1 electron to form 
ion
To form 
compound, 1 rubidium ion is needed to neutralize the charge on fluoride ion
The formation of the given compounds is shown in the image below.
Answer:
Option C. 251 kJ
Explanation:
The activation energy (Ea) of a given reaction is the minimum energy that must be overcomed for reactant to proceed to product.
The activation energy (Ea) can be obtained from an energy profile diagram by simply calculating the difference between the energy of the activation complex (i.e the peak) and the energy of the reactant.
Thus, we can obtain the activation energy for the reaction above as follow:
Activation complex = 332.6 kJ
Energy of reactant = 81.6 kJ
Activation energy =?
Activation energy = Activation complex – Energy of reactant
Activation energy = 332.6 – 81.6
Activation energy = 251 kJ
Therefore, the activation energy of the reaction is 251 kJ
From the given choices, aluminum oxide is the only ionic
compound there. The ions present are Al3+ and O2-. Aluminum is a
chemical compound of aluminum and oxygen with the chemical formula Al2O3. It is
the most frequently happening of numerous aluminum oxides, and precisely recognized
as aluminum (III) oxide.
Answer:
heterogeneous and homogeneous
Explanation:
la po ba abc?
Answer:
properties is the answer
there are about 115 elements, each of which has its own chemical. properties
