Answer:
The answer to your question is 6.77 atm
Explanation:
Data
Pressure 1 = P1 = 7.5 atm
Temperature 1 = T1 = 65°C
Pressure 2 = P2 = ?
Temperature 2 = T2 = 32°C
Process
-Use Gay-Lussac law to solve this problem
P1/T1 = P2/T2
-Solve for P2
P2 = P1T2 / T1
-Convert temperature to °K
T1 = 65 + 273 = 338°K
T2 = 32 + 273 = 305°K
-Substitution
P2 = (7.5 x 305) / 338
-Simplification
P2 = 2287.5 / 338
-Result
P2 = 6.77 atm
Answer:
9.9 ml of 0.200M NH₄OH(aq)
Explanation:
3NH₄OH(Iaq) + FeCl₃(aq) => NH₄Cl(aq) + Fe(OH)₃(s)
?ml of 0.200M NH₄OH(aq) reacts completely with 12ml of 0.550M FeCl₃(aq)
1 x Molarity NH₄OH x Volume Am-OH Solution(L) = 2 x Molarity FeCl₃ x Volume FeCl₃ Solution
1(0.200M)(Vol Am-OH Soln) = 3(0.550M)(0.012L)
=> Vol Am-OH Soln = 3(0.550M)(0.012L)/1(0.200M) = 0.0099 Liter = 9.9 milliliters
moles CO₂ = 5.57.10⁻⁴
<h3>Further explanation
</h3>
A mole is a number of particles(atoms, molecules, ions) in a substance
Can be formulated :
0.7% percent change with 3.5g of plant matter
mass :
moles :
Answer : The correct option is, (C) 0.675 M
Explanation :
Using neutralization law,
where,
= concentration of 
= 13.5 M
= concentration of diluted solution = ?
= volume of = 25.0 ml = 0.0250 L
conversion used : (1 L = 1000 mL)
= volume of diluted solution = 0.500 L
Now put all the given values in the above law, we get the concentration of the diluted solution.
Therefore, the concentration of the diluted solution is 0.675 M
Answer is: the percent composition of Hg in the compound is 71.5%.
Balanced chemical reaction: Hg + Br₂ → HgBr₂.
m(Hg) = 60.2 g; mass of the mercury.
m(Br₂) = 24.0; mass of the bromine.
m(HgBr₂) = m(Hg) + m(Br₂).
m(HgBr₂) = 60.2 g + 24 g.
m(HgBr₂) = 84.2 g; mass of the compound.
ω(Hg) = m(Hg) ÷ m(HgBr₂) · 100%.
ω(Hg) = 60.2 g ÷ 84.2 g · 100%.
ω(Hg) = 71.5%.
