Which statement about enzymes is true

Chemistry

1 answer:

artcher [175]3 years ago

3 0

The lower the activation energy required for a chemical reaction

You might be interested in

Use the ruler to determine the length of this object. Record your answer to the nearest tenth. The object is ____ long.

VLD [36.1K]

The object is 2.7 cm long

7 0

3 years ago

26 Which process occurs in an operating voltaic cell?(1) Electrical energy is converted to chemical energy.

tia_tia [17]

Answer is: (2) Chemical energy is converted to electrical energy.

An electrochemical cell (voltaic or galvanic cell) is generating electrical energy from chemical reactions.

In galvanic cell, specie (for example zinc and zinc cations) from one half-cell, lose electrons (oxidation) and species from the other half-cell (for example copper and copper cations) gain electrons (reduction).

Oxidation on the zinc anode: Zn(s) → Zn²⁺(aq) + 2e⁻.

Reduction on the copper cathode: Cu²⁺(aq) + 2e⁻ → Cu(s).

8 0

4 years ago

Read 2 more answers

How to balance Mg3n2+H20>>Mg(oh)2+Nh3?

alexandr1967 [171]

Mg₃N₂ + 6H₂O = 3Mg(OH)₂ + 2NH₃

4 0

3 years ago

what is the most appropriate unit to measure the following; the length of a football field. b) the diameter of a tennis ball

hjlf

Explanation:

a) m (metre)

b) mm (millimeter)

6 0

3 years ago

How much time would it take for 336 mg of copper to be plated at a current of 5.6 A ? Express your answer using two significant

schepotkina [342]

Answer:

1.8 × 10² s

Explanation:

Let's consider the reduction that occurs upon the electroplating of copper.

Cu²⁺(aq) + 2 e⁻ ⇒ Cu(s)

We will establish the following relationships:

1 g = 1,000 mg
The molar mass of Cu is 63.55 g/mol
When 1 mole of Cu is deposited, 2 moles of electrons circulate.
The charge of 1 mole of electrons is 96,486 C (Faraday's constant).
1 A = 1 C/s

The time that it would take for 336 mg of copper to be plated at a current of 5.6 A is:

$336mgCu \times \frac{1gCu}{1,000mgCu} \times \frac{1molCu}{63.55gCu} \times \frac{2mole^{-} }{1molCu} \times \frac{94,486C}{1mole^{-}} \times \frac{1s}{5.6C} = 1.8 \times 10^{2} s$

3 0

3 years ago