Answer:
0.142 M
Explanation:
Let's consider the neutralization reaction between calcium hydroxide and hydrochloric acid.
Ca(OH)₂ + 2 HCl → CaCl₂ + 2 H₂O
25.8 mL of 0.183 M HCl are used. The reacting moles are:
0.0258 L × 0.183 mol/L = 4.72 × 10⁻³ mol
The molar ratio of Ca(OH)₂ to HCl is 1:2. The reacting moles of Ca(OH)₂ are 1/2 × 4.72 × 10⁻³ mol = 2.36 × 10⁻³ mol
2.36 × 10⁻³ moles of Ca(OH)₂ are contained in 16.6 mL. The molarity of Ca(OH)₂ is:
M = 2.36 × 10⁻³ mol/0.0166 L = 0.142 M
Answer:
5.81 g/L
Explanation:
Let's apply the Ideal Gases Law to determine this:
P . V = n . R . T
Pressure = 1.6 atm
Volume = ?
Mol = 1 mol
Temperature = 96 K
In order to find the density, we should know the volume of the atmosphere which is a mixture of gases so, we consider all the atmosphere as a unique ideal gas.
1. 6 atm . V = 1 mol . 0.082 L.atm/mol.K . 96K
V = (1 mol . 0.082 L.atm/mol.K . 96K) / 1.6 atm
V = 4.92 L → As this is the volume for the whole atmosphere and the mass of 1 mol is 28.6 g, density should be:
28.6 g / 4.92L = 5.81 g/L
Density → mass / volume
Answer is: <span>b.20.0 L </span><span>liters of ammonia are needed to react completely.
</span>V(NO) = 30 L.
n(NO) = V(NO) ÷ Vm.
n(NO) = 30 L ÷ 22,4 L/mol.
n(NO) = 1,34 mol.
From chemical reaction: n(NO) : n(NH₃) = 6 : 4 (3 : 2).
n(NH₃) = 4 · 1,34 mol ÷ 6.
n(NH₃) = 0,892 mol.
V(NH₃) = 0,892 mol · 22,4 L/mol.
V(NH₃) = 20 L.
HCO3^1- because sodium has a 1+ charge
Answer:
If the 2nd and third 2 are underscored then there are two hydrogen atoms and 1 oxygen atom
Explanation: