Answer:
- Partial pressure He = 276 torr
- Partial pressure Ar = 457 torr
- Total pressure = 733 torr
Explanation:
Assuming temperature remains constant, we can use Boyle's law to solve this problem: P₁V₁=P₂V₂.
Once the two flasks are connected and the stopock opened, the total volume is:
Now we use Boyle's law <em>twice</em>, to <u>calculate the new pressure of </u><em><u>each</u></em><u> gas</u>:
- He ⇒ 752 torr * 275 mL = P₂He * 750 mL
P₂He = 276 torr
- Ar ⇒ 722 torr * 475 mL = P₂Ar * 750 mL
P₂Ar = 457 torr
Finally we <u>calculate the total pressure</u>, adding the partial pressures:
- Total pressure = P₂He + P₂Ar = 733 torr
<span>A substance that can be separated into two or more substances only by a chemical change is </span><span>known as a </span><span>heterogeneous</span><span> mixture</span>
hi have a nice day
will be less than 26 °C as water has a relatively higher specific heat than sand.
Explanation:
The specific heat of a substance is the amount of heat energy absorbed by one unit of mass of the substance when its temperature increases one unit.
From that, you can derive the equation for the specific heat of a substance:
specific heat = heat / (mass × ΔT)
Thus, assuming that all the heat provided by the lamp to both samples is the same and, as given, the amount (mass) of both samples is also the same, you have that the specific heat of the samples will be:
specific heat = constant / ΔT
So, specific heat and ΔT are inversely related.
It is known that water has a higher specific heat than sand (that is why the sand on the shore of a beach is, during the day, hotter than the water and your feet get burned when you walk on a sandy beach on a sunny day
There are 3 STOP codons in the genetic code - UAG, UAA, and UGA. These codons signal the end of the polypeptide chain during translation.
Answer:
Mass = 9.8 g
Explanation:
Given data:
Molarity of solution = 0.2 M
Volume of solution = 500 mL
Number of grams of phosphoric acid = ?
Solution:
First of all we will convert the volume milliliter to litter.
500 mL × 1 L/1000 mL
0.5 L
Molarity = moles of solute / volume in litter
0.2 M = number of moles / volume in litter
Number of moles = 0.2 mol/L × 0.5 L
Number of moles = 0.1 mol
Number of grams:
Number of moles = mass/molar mass
Mass = number of moles × molar mass
Mass = 0.1 mol × 98 g/mol
Mass = 9.8 g
