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alexdok [17]
3 years ago
9

a student determines. 8.2 mg of oxygen is dissolved in a 1000 gram sample of water at 15° Celsius what type of solution is the s

ample
Chemistry
1 answer:
Viefleur [7K]3 years ago
4 0

We do not know. We have not been given the solubility of oxygen in water at a given temperature nor have we been given the Henry's laws constant. We also do not know whether you mean 1 atmosphere of air, or 1 atmosphere of oxygen.

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Which kingdom does extreme microbe belong to
Ipatiy [6.2K]

Answer:prokaryotes

Explanation:

7 0
3 years ago
In the reaction of aluminum and iron(iii) oxide to form iron and aluminum oxide, δh is - 850 kj. how many grams of aluminum oxid
Semmy [17]
The  grams  of   aluminium  oxide  are  formed when  350  kj  heat  are  released is calculated  as  follows

1mole  =  850Kj
what  about  350kj
=1mole  x350/850  =  0.412  moles

mass  of  Al =   moles  of  Al x  molar  mass of  Al

=  0.412mol  x  27  g/mol  =  11.124  grams
8 0
3 years ago
Un atleta se dirige hacia la línea de salida a 6 m/s. Cuando pasa por la marca de 100 m, ponemos el cronómetro en marcha. Escrib
Romashka [77]

Answer:

Los parámetros dados del movimiento son;

La velocidad con la que el atleta se dirige hacia la línea de salida = 6 m / s

El punto en el que se inicia el cronómetro = marca de 100 m

La ecuación para la distancia recorrida, 's', se da como sigue;

s = 6 m / s × t

La distancia total recorrida, d = 100 + s

∴ d = 100 + 6·t

Los gráficos de las ecuaciones se crean con Microsoft Excel y se presentan de la siguiente manera;

Explanation:

4 0
3 years ago
Give two examples of rocks composed of only one material.
Marysya12 [62]

Answer:

pyroxenite, quartzite, dunite (over 90% olivine), anorthosite (over 90% plagioclase feldspar), marble, chalk, gypsum

Explanation:

6 0
4 years ago
Recall that your hypothesis is that these values are the fraction of atoms that are still radioactive after n half-life cycles.
jolli1 [7]

Answer : A= 0.5, B = 0.25 , C = 0.125, D = 0.015625 and E = 0.00390625

Explanation :

Half life of a substance is defined as the amount of time taken by the substance to reduce to half of its original amount.

Here n represents the number of half lives.

The amount of substance that remains after n half lives can be calculated using the given formula, 0.5^{n}

So when we have n =1,

Fraction of substance that remains = 0.5¹ = 0.5.

That means after first half life over, the amount of substance that remains is 0.5 times that of original.

Therefore we have A = 0.5

When n = 2, we have 0.5² = 0.25

So when 2 half lives are over, the amount of substance that remains is 0.25 times that of original

Therefore B = 0.25

When n = 3, we have 0.5³ = 0.125

So when 3 half lives are over, the amount of substance that remains is 0.125 times that of original.

Therefore we have C = 0.125

When n = 6 , we have 0.5⁶ = 0.015625

So D = 0.015625

When n = 8, we have 0.5⁸ = 0.00390625

Therefore E = 0.00390625

The values for A, B, C, D and E are 0.5, 0.25, 0.125, 0.015625 and 0.00390625 respectively.

8 0
3 years ago
Read 2 more answers
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