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Serga [27]
3 years ago
7

Two cars are traveling at the same constant speed v. Car A is moving along a straight section of the road, while B is rounding a

circular turn. Which statement is true about the acceleration of the cars?
a.) acceleration of both cars is zero
b.) car A is accelerating but car B isnt.
c.) car A is not acc, but car B is
d.) both car accelerate.
Physics
1 answer:
mel-nik [20]3 years ago
4 0

Answer:

(D) Car A is not accelerating, but car B is accelerating.

Explanation:

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Hey guys can y’all help quickly?
Naddik [55]

Answer:

Temporary? You have two options

If you have a positively charged object, bring it close to the LEFT side of the ball (not touching it!).

If you have a negatively charged object, bring it close to the RIGHT side of the ball (again, not in contact).

Either way, the electron cloud will migrate towards the right side of the of your sphere.

Another option is to have a capacitor large enough to house the sphere inside it, and polarize it by attaching it to a DC source making sure that the negative plate of it is to the right of the sphere.

7 0
2 years ago
Collins body metabolizes caffeine at a rate of 14.3% per hour (so the amount of caffeine in Collins body decreases by 14.3% each
Oksanka [162]

Answer:

It will take 4.5 h to metabolize 50% of the ingested caffeine.

Explanation:

Hi there!

We have to find how long will it take Collin´s body to metabolize 50% (40 g) of the ingested caffeine. We know that Collin´s body metabolizes 14.3 % of the amount of caffeine each hour. Then, every hour the caffeine will be reduced by 14.3 %.

After the first hour, the amount of caffeine will be:

80 - 80 · 0.143 = 68.56

Expressed in other form

80 · (1 - 0.143) = 68.56

80 · 0.857 = 68.56

After the second hour, the amount of caffeine will be:

68.56 - 68.56 · 0.143 = 58.75592

or

68.56 · 0.857 =  58.75592

Since 68.56 = 80 · 0.857, we could write the amount of caffeine after 2 hours as:

80. 0.857 · 0.857  =  58.75592

After the third hour:

58.75592 - 58.75592 · 0.143 = 50.35382344

or

58.75592 · 0.857 = 50.35382344

In the same way, since 58.75592 = 80. 0.857 · 0.857  the amount of caffeine after 3 hours will be:

80. 0.857 · 0.857  · 0.857 = 50.35382344

Then after x hours, the amount of caffeine in the body will be:

80 mg · 0.857ˣ

We have to find the value of x for which that expression is equal to 40 mg:

80 mg · 0.857ˣ = 40 mg

0.857ˣ = 40 mg/ 80 mg

0.857ˣ = 0.5

Apply ln to both side of the equation:

ln(0.857ˣ) = ln(0.5)

Apply logarithm property : ln(xᵃ) = a ln(x)

x ln(0.857) = ln(0.5)

x = ln(0.5)/ln(0.857)

x = 4.5 h

It will take 4.5 h to metabolize 50% of the ingested caffeine.

3 0
3 years ago
In first equation of motion at denotes​
RideAnS [48]

Answer:

Names of the Equations of Motion

1 The First Equation of Motion is, v=u+at is known as velocity – time relation. 2 The Second Equation of Motion is, s=ut+12at2 is known as position – time relation.

6 0
3 years ago
The graph indicates Linda’s walk.
Sedaia [141]
I think the right answer is the first one. If she stops moving her Position does not change any more-and the Graph Shows that after 6 seconds she stays at the Position of 5 m. If she Went Back to the start point the Graph would have Developed Back to 0m(decreased).
3 0
4 years ago
Read 2 more answers
he measured flow rate of water through a 20 mm diameter pipe is 75 L/min. What is the average velocity (in m/s) of water flowing
Masteriza [31]

Answer:

Average velocity of water flow through the pipe = 3.98 m/s

Explanation:

Diameter of pipe = 20 mm

Discharge = 75 L/min

We know that

        Discharge = Area x Velocity

      \texttt{Area of pipe}=\frac{\pi d^2}{4}=\frac{\pi \times (20\times 10^{-3})^2}{4}=3.14\times 10^{-4}m^2

       Discharge = 75 L/min

                         =\frac{75\times 10^{-3}}{60}=1.25\times 10^{-3}m^3/s

Substituting

        1.25\times 10^{-3}=3.14\times 10^{-4}\times V\\\\V=3.98m/s

Average velocity of water flow through the pipe = 3.98 m/s

6 0
3 years ago
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