What species do humans belong to

One recently discovered extrasolar planet, or exoplanet, orbits a star whose mass is 0.70 times the mass of our sun. This planet

Stels [109]

0.078 times the orbital radius r of the earth around our sun is the exoplanet's orbital radius around its sun.

Answer: Option B

<u>Explanation:</u>

Given that planet is revolving around the earth so from the statement of centrifugal force, we know that any

$\frac{G M m}{r^{2}}=m \omega^{2} r$

The orbit’s period is given by,

$T=\sqrt{\frac{2 \pi}{\omega r^{2}}}=\sqrt{\frac{r^{3}}{G M}}$

Where,

$T_{e}$ = Earth’s period

$T_{p}$ = planet’s period

$M_{s}$ = sun’s mass

$r_{e}$ = earth’s radius

Now,

$T_{e}=\sqrt{\frac{r_{e}^{3}}{G M_{s}}}$

As, planet mass is equal to 0.7 times the sun mass, so

$T_{p}=\sqrt{\frac{r_{p}^{3}}{0.7 G M_{s}}}$

Taking the ratios of both equation, we get,

$\frac{T_{e}}{T_{p}}=\frac{\sqrt{\frac{r_{e}^{3}}{G M_{s}}}}{\sqrt{\frac{r_{p}^{3}}{0.7 G M_{s}}}}$

$\frac{T_{e}}{T_{p}}=\sqrt{\frac{0.7 \times r_{e}^{3}}{r_{p}^{3}}}$

$\left(\frac{T_{e}}{T_{p}}\right)^{2}=\frac{0.7 \times r_{e}^{3}}{r_{p}^{3}}$

$\left(\frac{T_{e}}{T_{p}}\right)^{2} \times \frac{1}{0.7}=\frac{r_{e}^{3}}{r_{p}^{3}}$

$\frac{r_{e}}{r_{p}}=\left(\left(\frac{T_{e}}{T_{p}}\right)^{2} \times \frac{1}{0.7}\right)^{\frac{1}{3}}$

Given $T_{p}=9.5 \text { days }$ and $T_{e}=365 \text { days }$

$\frac{r_{e}}{r_{p}}=\left(\left(\frac{365}{9.5}\right)^{2} \times \frac{1}{0.7}\right)^{\frac{1}{3}}=\left(\frac{133225}{90.25} \times \frac{1}{0.7}\right)^{\frac{1}{3}}=(2108.82)^{\frac{1}{3}}$

$r_{p}=\left(\frac{1}{(2108.82)^{\frac{1}{3}}}\right) r_{e}=\left(\frac{1}{12.82}\right) r_{e}=0.078 r_{e}$

7 0

3 years ago

Please help!!! zoom in to read it clearly

Artist 52 [7]

Answer:

imma try nd help cuz i havent seen anybody answer so

1.sara

2.same for both

3.tom

Explanation:

4 0

3 years ago

Item 8 The cost (in dollars) of making b bracelets is represented by 4 5b. The cost (in dollars) of making b necklaces is repres

grin007 [14]

Answer:

3b+2

Explanation:

First your question has so many mistakes

What I understand

bracelets cost 4+5b

necklaces cost 8b+6

First we have to make an equaion

=(8b+6)-(4+5b)

simplify it

=8b+6-4-5b

=3b+2 Answer

4 0

3 years ago

What is the mass of .5 newtons(N)?

ddd [48]

Since the mass is 5 grams the acceleration is: 4000 m/s^2

But if the mass is 5 Kilograms the acceleration is: 4 m/s^2

7 0

3 years ago

My Notes A container is divided into two equal compartments by a partition. One compartment is initially filled with helium at a

Ostrovityanka [42]

Answer:

$final-temperature = T_{f} = 252.51K$

Explanation:

we can solve this problem by using the first law of thermodynamics.

$\Delta U= Q-W$

Q= heat added

U= internal energy

W= work done by system

$E_{final}= E_{initial}$

$C_{v}(N_{2})=1.04\frac{KJ}{Kg K}$

$C_{v}(He)=5.193\frac{KJ}{Kg K}$

now

From equation 1

$T_{f}=\frac{C_{v}( N_{2}) T_{N_{2} } C_{v} (He) T_{He}}{C_{v} (N_{2}) C_{v}(He)}$

$T_{f} = \frac{315\times1.04+5.193\times240}{1.04+5.193}$

$T_{f} = 252.51K$

4 0

4 years ago