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3 years ago

Please help on questions D AND E and please show working out as well so I can understand better thank you only QUESTIONS D AND E

Physics

1 answer:

tester [92]3 years ago

5 0

Answer:

d. 87,500 J

e. 49,600 J

Explanation:

The total energy is the heat absorbed by the copper plus the heat absorbed by the water.

E = m₁C₁ΔT + m₂C₂ΔT

E = (1 kg) (390 J/kg/°C) (10 °C) + (2 kg) (4180 J/kg/°C) (10 °C)

E = 87,500 J

E = m₁C₁ΔT + m₂C₂ΔT

E = (2 kg) (390 J/kg/°C) (10 °C) + (1 kg) (4180 J/kg/°C) (10 °C)

E = 49,600 J

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1. Due to the first law of Newton: there is a force that accelerate the body,

then the net force for 2 forces in opposite directions can calculated as

$F_{net}=F_{1}-F_{2}=26-8=14N$

2. For a force make an angle with the horizontal plane, we need to analysis the force into 2 perpendicular forces:

- In horizontal plane:

$F_{x}=Fsin ($ θ $)= 67sin(73)=64N$

then, as Q(1),

$F_{net}=F_{1}-F_{2}=64-33=31 N$

3. Because of the non change in the velocity, there is no acceleration

Then, there is no force is acted from the body

Hence all forces is according to the tension in the cable

$F_{Tension}=420 N$

4. A) As we solve the Q(2), we will analysis the un horizontal or vertical forces into 2 forces

$F_{x}=Fsin ($ θ $)= 600sin(45)=424.264N$

$F_{y} = F sin ($ θ $)= 600cos45)=424.264N$

Hence we have 2 opposite horizontal forces. also, 2 opposite vertical forces.

now, we calculate the net forces in each direction

$F_{net in x}=F_{1}-F_{2}=424.264-250=174.264 N$ in east

$F_{net in y}=F_{1}-F_{2}=-500-424.264=75.736 N$ in south

The total net force for perpendicular forces is calculated from the relation:

$F_{total}=\sqrt{F_{x} ^{2}+F_{y}^{2}}=\sqrt{174.264^{2}+75.736^{2}}=190N$

B) To find the direction, we need to calculate the angle which the total force is made with the east direction of the x-axis (horizontal)

θ = $tan^{-1}(\frac{F_{y}}{F_{x} })= tan^{-1}(\frac{-75.736}{174.264})=-23.48^{o}$

That meas that the total force is made with the east direction of the x-axis angle equal to 23.48 for the south (the 4th quarter)

5. According to the third law of Newton, to make the balance the net force equal to zero (for each action there is a reaction with the same amplitude and in opposite direction)

Then, $F_{right}=F_{left}=55N$

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4 years ago