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Korvikt [17]
3 years ago
8

Could something small like a baseball have as much momentum as car

Physics
2 answers:
RideAnS [48]3 years ago
8 0

Is the answer a yes or no question? Because if so i think it would be yes.

Rina8888 [55]3 years ago
3 0

Yes.  Definitely, uh huh, and fer sher.

Momentum is the product of (mass) times (speed).

So it doesn't matter how tiny the mass is.  If the speed is great enough, then the tiny object can have the same momentum as the massive object, or even more.

(That's the whole deal with bullets.)

You might be interested in
An airplane propeller is 2.68 m in length (from tip to tip) and has a mass of 107 kg. When the airplane's engine is first starte
telo118 [61]

Answer:

a)30.14 rad/s2

b)43.5 rad/s

c)60633 J

d)42 kW

e)84 kW

Explanation:

If we treat the propeller is a slender rod, then its moments of inertia is

I =\frac{mL^2}{12} = \frac{107*2.68^2}{12} = 64.04 kgm^2

a. The angular acceleration is Torque divided by moments of inertia:

\alpha = \frac{T}{I} = \frac{1930}{64.04} = 30.14 rad/s^2

b. 5 revolution would be equals to 10\pi rad, or 31.4 rad. Since the engine just got started

\omega^2 = 2\alpha\theta = 2*30.14*31.4 = 1893.5

\omega = \sqrt{1893.5} = 43.5 rad/s

c. Work done during the first 5 revolution would be torque times angular displacement:

W = T*\theta = 1930 * 31.4 = 60633 J

d. The time it takes to spin the first 5 revolutions is

t = \frac{\omega}{\alpha} = \frac{43.5}{30.14} = 1.44 s

The average power output is work per unit time

P = \frac{W}{t} = \frac{60633}{1.44} = 41991 W or 42 kW

e.The instantaneous power at the instant of 5 rev would be Torque times angular speed at that time:

P_i = T*\omega = 1930*43.5=83983 W or 84 kW

7 0
2 years ago
The speed of an aircraft is measure in the unit_​
slega [8]

Answer:

knot...

.....

.....

.....

8 0
1 year ago
What is the weight of a feather (mass = 0.0001 kg) that floats through earth's and the moon's atmospheres?
Dvinal [7]

Weight = (mass) x (acceleration of gravity)

Acceleration of gravity = 9.81 m/s² on Earth, 1.62 m/s² on the Moon.

The feather's weight is . . .

On Earth:  (0.0001 kg) x (9.81 m/s²) = <em>0.000981 Newton </em>

On the Moon:  (0.0001 kg) x (1.62 m/s²) = <em>0.000162 N</em>

The presence or absence of atmosphere makes no difference.  In fact, the numbers would be the same if the feather were sealed in a jar, or spinning wildly in a tornado, or hanging by a thread, or floating in a bowl of water or chicken soup.  Weight is just the force of gravity between the feather and the Earth.  It's not affected by what's around the feather, or what's happening to it.

6 0
2 years ago
5. a stone propelled from a catapult with a speed of 50 m/s attains a height of 100m. Calculate
omeli [17]

Answer:

<h3>The answer is 2 s</h3>

Explanation:

The time of flight can be found by using the formula

t =  \frac{d}{v}  \\

d is the distance covered

v is the velocity

From the question we have

t =  \frac{100}{50}  =  \frac{10}{5}  \\

We have the final answer as

<h3>2 s</h3>

Hope this helps you

8 0
2 years ago
A sound wave can be considered as a displacement wave or a pressure wave? What phase difference exists between the displacement
netineya [11]
Where the displacement is a maximum the pressure is a minimum.
Where the displacement is zero, the pressure is a maximum.
3 0
3 years ago
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