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Korvikt [17]
4 years ago
8

Could something small like a baseball have as much momentum as car

Physics
2 answers:
RideAnS [48]4 years ago
8 0

Is the answer a yes or no question? Because if so i think it would be yes.

Rina8888 [55]4 years ago
3 0

Yes.  Definitely, uh huh, and fer sher.

Momentum is the product of (mass) times (speed).

So it doesn't matter how tiny the mass is.  If the speed is great enough, then the tiny object can have the same momentum as the massive object, or even more.

(That's the whole deal with bullets.)

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Volcanoes change the earth by (2 points) slow surface heating violent, fast eruptions rapid oxygen depletion keeping mountains f
Ivanshal [37]

Is this your own answer after the 2 points because if so i would say that is a good answer exept for keeping mountains from growing but they do cause giant black clouds that can block sunlight from the ground below

3 0
3 years ago
A gun can fire a bullet at 540 m/s. If the gun is aimed at an angle of 55o above the horizontal and fired, what will be the hori
lisabon 2012 [21]

Answer:

Explanation:

The <u>initial</u> vertical velocity is 540sin55° = 442.342103... 442 m/s

The <u>initial</u> horizontal velocity is 540cos55° = 309.731275... 310 m/s

In the real world, both initial velocities would be reduced by air resistance and vertical velocity will be altered by gravity.

5 0
3 years ago
What waves have high amplitudes
Olegator [25]

-- loud sounds

-- bright lights

-- strong radio signals

-- Slinkies that can pinch you painfully

-- a tsunami in the ocean

-- earthquakes above Richter 5 or 6

5 0
4 years ago
An average person can reach a maximum height of about 60 cm when jumping straight up from a crouched position. During the jump i
Iteru [2.4K]

Answer:

Explanation:

Height attained by body = 50 cm

= .5 m

Initial velocity = u

v² = u² - 2gh

0 = u² - 2gh

u² = 2 x 9.8 x .5

u = 3.13 m /s

During the initial period , the muscle stretches by around 10 cm during which force by ground reacts on the body and gives acceleration to achieve velocity of 3.13 m/s from zero .

v² = u² + 2as

3.13² = 0 + 2 a x .10

a = 49  m/s²

reaction by ground R

Net force

R-mg = ma

R= m ( g +a )

= mg + ma

=W + (W/g) x a

W ( 1 + a / g )

= W ( 1 + 49 / 9.8 )

= 6W

4 0
4 years ago
A conductor shaped as a circular loop with a radius of 4.0 m is located in a uniform but changing magnetic field. If the maximum
bekas [8.4K]

Answer:

\frac{\delta B}{\delta t}= 0.0995 \  T/s

Explanation:

Given that :

The radius of the circular loop = 4.0 m

Maximum Emf E_{max} = 5.0 V

The  maximum rate at which the magnetic field strength is changing if the magnetic field is oriented perpendicular to the plane in which the loop lies can be determined via the expression;

E_{max} = Area (A) * \frac{\delta B}{\delta t}

E_{max} = \pi r^2 * \frac{\delta B}{\delta t}

5.0 = \pi * (4.0)^2 * \frac{\delta B}{\delta t}

5.0 = 50.27 * \frac{\delta B}{\delta t}

\frac{\delta B}{\delta t}= \frac{5}{50.27}

\frac{\delta B}{\delta t}= 0.0995 \  T/s

5 0
3 years ago
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