Ask question

Ask question

All categories

3 years ago

12

Sensitive science experiment needs to be isolated from vibrations. the experiment sits in a cradle that dampens low frequency vi

brations (such as from a passing train. what change would best isolate the experiment from higher frequency vibrations?

1 answer:

nignag [31]3 years ago

5 0

Move away from any place that moves like California

You might be interested in

According to the cooling curve, what is the approximate freezing point of the substance?

Oksana_A [137]

Answer:

I do not know which substance you are referring to, but the freezing point of water is 32°F, or 0°C.

3 0

3 years ago

Feliz [49]

Answer:

100 V

Explanation:

Hi there!

Ohm's law states that $V=IR$ where V is the voltage, I is the current and R is the resistance.

Plug the given information into Ohm's law (R=50, I=A)

$V=IR\\V=(2)(50)\\V=100$

Therefore, the voltage across this current is 100 V.

I hope this helps!

6 0

3 years ago

-4, 0, -2/3, 4.11111…, 2, π, √6 'which members of this set are irrartional?

krok68 [10]

An irrational number is a real number that cannot be written as a simple fraction.

4 = 4/1 = rational

0 = 0/1 = rational

-2/3 = rational

4.11111 = irrational

2 = 2/1 = rational

π = 3.141592... = irrational

√6= irrational

Answer:

4.1111, π , √6

3 0

1 year ago

Which is an example of colloid

bulgar [2K]

Colloid mixtures can be solids, liquids, or gases. EX- Would include, butter, milk, and frog. There are actually 8 types of colloid mixtures, they are usally described by orginal state.

7 0

3 years ago

A(n) 10.1 g bullet is fired into a(n) 2.41 kg ballistic pendulum and becomes embedded in it. The acceleration of gravity is 9.8

fomenos

Answer:

$v = 186.90\,\frac{m}{s}$

Explanation:

The motion of ballistic pendulum is modelled by the appropriate use of the Principle of Energy Conservation:

$\frac{1}{2}\cdot (m_{p}+m_{b})\cdot v^{2} = (m_{p}+m_{b})\cdot g \cdot h$

The final velocity of the system formed by the ballistic pendulum and the bullet is:

$v = \sqrt{2\cdot g\cdot h}$

$v = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot (0.031\,m)}$

$v\approx 0.78\,\frac{m}{s}$

Initial velocity of the bullet can be calculated from the expression derived of the Principle of Momentum:

$(0.0101\,kg)\cdot v = (2.41\,kg + 0.0101\,kg)\cdot (0.78\,\frac{m}{s} )$

$v = 186.90\,\frac{m}{s}$

5 0

3 years ago