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FromTheMoon [43]
3 years ago
7

Which of these is an uneven rhythm movement? Question 5 options:

Physics
2 answers:
Musya8 [376]3 years ago
8 0

Answer:

Sliding would be an uneven rhythm because Galloping and skipping has a constant flow of the same movement and same noise.

Explanation:

vredina [299]3 years ago
8 0
I think that the answer is slinging
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Which of the following describes a condition in which an individual would not hear an echo?
IrinaVladis [17]
If the echo (the reflected sound) reaches your ear less than about
0.1 second after the original sound, your brain doesn't separate them,
and you're not aware of the echo even though it's there.

If the echo comes from, say, a wall, 0.1 second means you'd have to be
about  17 meters away from the wall.  If you're closer than that, then the
echo reaches you in less than 0.1 second and you're not aware of it.

A. 30 meters . . .
     No.  You hear that echo easily

B.  you're standing within range of both sounds . . .
     No. You hear that echo easily, if you're at least 17 meters from the wall.

C.  less than 0.1 second later . . .
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D.  21.5 meters
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4 0
3 years ago
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Olenka [21]
The basis for Rutherford's Planetary model, was the results he got from experiments.

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3 0
3 years ago
100 J of work in 10 seconds
HACTEHA [7]
The average power is 10 watts. What's the question ?
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3 years ago
What effect does a catalyst have on the energy of a reaction system? HELP ASAP PLZ!!
Lubov Fominskaja [6]

Answer:

I think option A is correct

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5 0
3 years ago
If a player through a basketball to the target with an initial velocity of 17 m/s making an angle of 30 degrees with the horizon
Svetllana [295]

Answer:

The final position made with the vertical is 2.77 m.

Explanation:

Given;

initial velocity of the ball, V = 17 m/s

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time of motion, t = 1.3 s

The vertical component of the velocity is calculated as;

V_y = Vsin \theta\\\\V_y = 17 \times sin(30)\\\\V_y = 8.5 \ m/s

The final position made with the vertical (Yf) after 1.3 seconds is calculated as;

Y_f = V_yt  - \frac{1}{2}g t^2\\\\Y_f = (8.5 \times 1.3 ) - (\frac{1}{2} \times 9.8 \times 1.3^2)\\\\Y_f = 11.05 \ - \ 8.281\\\\Y_f = 2.77 \ m

Therefore, the final position made with the vertical is 2.77 m.

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