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FromTheMoon [43]
3 years ago
7

Which of these is an uneven rhythm movement? Question 5 options:

Physics
2 answers:
Musya8 [376]3 years ago
8 0

Answer:

Sliding would be an uneven rhythm because Galloping and skipping has a constant flow of the same movement and same noise.

Explanation:

vredina [299]3 years ago
8 0
I think that the answer is slinging
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A wave has a frequency of 775 Hz. What is its period?
Leto [7]

The period is simply the inverse of the frequency, therefore:

T = 1 / f

T = 1 / 775 Hz

T = 0.001290 s    → possible answer

T = 1.29 × 10⁻³ s   → possible answer

T = 1.29 ms          → possible answer

4 0
3 years ago
A man pulls on his dog's leash to keep him from running after a bicycle. Which term best describes this example?
otez555 [7]
We know the answer doesn't have to do with force because we have not identified a positive or negative axis. 

Depending on what the system we are evaluating is, the sign of the work can change.

If work is done on the system, it is negative, but if work is done by the system, it is positive. 

If the system we are evaluating is the leash, the work is being done by the leash, and therefore, the work is positive.

If the system we are evaluating is the dog, the work is being done on the dog, and therefore, the work is negative.


8 0
3 years ago
Read 2 more answers
→15 points← Waiting for his new game to come in the mail, Billy races up the stairs in 3 seconds from the basement whenever he h
stich3 [128]

Answer:

500 Newton’s 3 meters high

Explanation:

3 0
3 years ago
Dos bolas, de masas mA = 40 g y mB =60 g, esta?n suspendidas como se observa en la figura. La bola ma?s ligera se jala en un a?n
Ymorist [56]
MA=40 or something I really don’t know
3 0
3 years ago
You are working as an assistant to an air-traffic controller at the local airport, from which small airplanes take off and land.
Alika [10]

Answer:

d = 2021.6 km

Explanation:

We can solve this distance exercise with vectors, the easiest method s to find the components of the position of each plane and then use the Pythagorean theorem to find distance between them

Airplane 1

Height   y₁ = 800m

Angle θ = 25°

           cos 25 = x / r

           sin 25 = z / r

           x₁ = r cos 20

           z₁ = r sin 25

          x₁ = 18 103 cos 25 = 16,314 103 m = 16314 m

          z₁ = 18 103 sin 25 = 7,607 103 m= 7607 m

2 plane

Height   y₂ = 1100 m

Angle θ = 20°

          x₂ = 20 103 cos 25 = 18.126 103 m = 18126 m

          z₂ = 20 103 without 25 = 8.452 103 m = 8452 m

The distance between the planes using the Pythagorean Theorem is

         d² = (x₂-x₁)² + (y₂-y₁)² + (z₂-z₁)²2

Let's calculate

        d² = (18126-16314)²  + (1100-800)² + (8452-7607)²

        d² = 3,283 106 +9 104 + 7,140 105

        d² = (328.3 + 9 + 71.40) 10⁴

        d = √(408.7 10⁴)

        d = 20,216 10² m

        d = 2021.6 km

7 0
4 years ago
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