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Lerok [7]
3 years ago
8

What is the equation to find an angle of projectile

Physics
1 answer:
Ksju [112]3 years ago
3 0
I do not recall the answer to this question
You might be interested in
What is the approximate energy required to raise the temperature of 1.00 L of hydrogen by 90 °C? The pressure is held constant a
Oliga [24]

Answer:

Q = 116.8 J

Explanation:

Here given that the temperature of 1 L hydrogen is increased by 90 degree C at constant pressure condition.

So here we will have

Q = n C_p \Delta T

here we know that

n = number of moles

n = \frac{1}{22.4}

n = 0.0446

for ideal diatomic gas molar specific heat capacity at constant pressure is given as

C_p = \frac{7}{2}R

now we have

Q = (0.0446)(\frac{7}{2}R)(90)

Q = 116.8 J

3 0
3 years ago
2 Name the device in a car that we use to change the speed of the car
Crank

Answer:

Speedometer

Explanation:

Have a good day! :3

6 0
2 years ago
A friend frequently misses the morning
poizon [28]

Answer: Heyaa! ~

State of the problem is that your friend routinely misses the school bus.

Explanation:

What are the causes for his missing the school bus:

  • Not waking<em> early </em>enough
  • Too<em> long</em> breakfast
  • Too<em> far</em> to the bus stop.
  • <em>Deliberately</em> tries to miss the bus.

Hopefully this helps you!

-Matthew ^^

7 0
2 years ago
What type of blood vessel returns blood to the heart?
djyliett [7]
The superior and inferior vena cava are collectively called the venae cavae. The venae cavae, along with the aorta, are the great vessels involved in systemic circulation. These veins return deoxygenated blood from the body into the heart, emptying it into the right atrium.
5 0
3 years ago
You are on the roof of the physics building, 46.0 above the ground . Your physics professor, who is 1.80 tall, is walking alongs
Fudgin [204]

Answer:

3.6m

Explanation:

if you are at a building that is 46m above the ground, and the professor is 1.80m, the egg must fall:

46m - 1.80m = 44.2m

the egg must fall for 44.2m to land on the head of the professor.

Now, how many time this takes?

we have to use the following free fall equation:

h=v_{0}t+\frac{1}{2}gt^2

where h is the height, v_{0} is the initial velocity, in this case v_{0}=0. g is the acceleration of gravity: g=9.81m/s and t is time, thus:

h=\frac{1}{2}gt^2

clearing for time:

2h=gt^2\\\frac{2h}{g}=t^2\\\sqrt{\frac{2h}{g}} =t

we know that the egg has to fall for 44.2m, so h=44.2, and g=9.81m/s, so we the time is:

t=\sqrt{\frac{2(44.2m)}{9.8m/s^2} }=\sqrt{\frac{88.4m}{9.81m/s^2} } =\sqrt{9.011s^2}= 3.002s

Finally, if the professor has a speed of v=1.2m/s, it has to be at a distance:

d=vt

and t=3.002s:

d=(1.2m/s)(3.002s)=3.6m

so the answer is the professor has to be 3.6m far from the building when you release the egg

7 0
3 years ago
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