To solve this problem it is necessary to apply the concepts related to the kinematic equations of motion for which the height of a particle is defined as a function of gravity as,
Where,
h = Height
g = Gravity constant
v = Velocity
There is not change in the horizontal component, therefore there is only the component horizontal given (18m/s) and the vertical component:
Applying the vector theory to find the magnitude of a vector we have to
The speed at which the ball was thrown was 25.38
Answer:
26.5 m/s
Explanation:
The tension in the string provides the centripetal force that keeps the toy in circular motion. So we can write:
where:
T is the tension in the spring
m = 0.50 kg is the mass of the toy
r = 1.0 m is the radius of the circle (the length of the string)
v is the speed of the toy
The maximum tension in the string is
T = 350 N
If we substitute this value into the equation, we find the maximum speed that the mass can have before the string breaks:
Question:
Assumptions
Voltage of battery = 24 V
Resistance on the right,20Ω parallel to 10 Ω resistor
Answer:
For the current out of the battery to be the same as when the switch was opened with the switch closed, the resistance on the resistor on the right must be approximately 20/3 Ω
Explanation:
We note that the switch in the assumption is on the same line as the 20 Ω resistor.
With a voltage of 24 V, and the switch closed, we have;
Total resistance =
Current out of voltage, I = Voltage/(total resistance)
= 24 ÷ 20/3 = 24 × 3/20 = 18/5 A
Therefore, with the switch opened, we get
Resistance on the right = Initial total resistance
Therefore, with the switch opened, the resistance on the resistor on the right must be approximately equal to the resultant resistance of the two resistances in parallel.