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Paul [167]
1 year ago
10

The pressure exerted by each individual gas in a mixture of gases is called its pressure. This pressure is proportional to the f

raction of the gas in the mixture.
Chemistry
1 answer:
snow_lady [41]1 year ago
3 0

The pressure exerted by each individual gas in a mixture of gases is called its <u>partial </u>pressure this pressure is proportional to the <u>mole</u> fraction of the gas in the mixture

Pressure is defined as the force of all the gas particle of wall collisions divided by the area of the wall

The pressure exerted by an individual gas in a mixture is known as its partial pressure and assuming we have a mixture of ideal gases and we can use the ideal gas law to solve problems involving gases in a mixture and the ratio of the number of moles of one component of a solution or other mixture to the total number of moles representing all of the components

Know more about pressure

brainly.com/question/16118479

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Which of the following are functions of the ears?
vazorg [7]

Answer:

A. and C.

Explanation:

The ears job is to keep our body at the right temperature while hearing sounds.

6 0
2 years ago
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What's the amount of solute in 1.75 L of 0.25 M HCl?
Fynjy0 [20]

Answer: 0.4375 mols of solute

Explanation:

The problem is asking for the amount of solute. We are given the value of molarity. The molarity is 0.25M. We know that molarity is M=\frac{mols of solute}{liters of solution}. Since we are given the liters of solution is 1.75, we can use those values to solve for mols of solute.

0.25M=\frac{x}{1.75L}                        [multiply both sides by 1.75 L]

x=0.4375 mols

There are 0.4375 mols of solute.

5 0
3 years ago
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Crazy boy [7]
Usual s I have no idea sorry
6 0
4 years ago
An 8.42 g piece of metal with a specific heat of 1.020 J g-1 k-1 wasn't heated to an unknown temperature. The metal was then pla
ANTONII [103]

Answer:

T = 61.344\,^{\textdegree}C

Explanation:

The heat received by water is equal to the heat rejected by the piece of metal. That is to say:

-Q_{piece} = Q_{water}

(8.42\,g) \cdot \left(1.020\,\frac{J}{g\cdot ^{\textdegree}C}  \right) \cdot (T - 20.40\,^{\textdegree}C)= (44.2\,g)\cdot \left(4.187\,\frac{J}{g\cdot ^{\textdegree}C} \right)\cdot (20.40\,^{\textdegree}C-18.50\,^{\textdegree}C)

\left(8.588\,\frac{J}{^{\textdegree}C} \right)\cdot (T-20.40\,^{\textdegree}C) = 351.624\,J

The initial temperature of the piece of metal is:

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4 0
3 years ago
Read 2 more answers
An analytical chemist is titrating of a solution of ammonia with a solution of . The of ammonia is . Calculate the pH of the bas
harina [27]

Answer: The question has some details missing. here is the complete question ; An analytical chemist is titrating 88.4 mL of a 0.2700 M solution of ammonia (NH3 with a 0.4300 M solution of HNO3. The pK, of ammonia is 4.74 Calculate the pH of the base solution after the chemist has added 66.3 mL of the HNO3 solution to it . Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO3 solution

Explanation:

Given ;

  • number of moles of base = 88.4 x 0.2700 = 23.868
  • number of moles of acid = 0.4300 x 66.3 = 28.509
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7 0
3 years ago
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