Answer:
The first equation
Explanation:
For these problems, it is best to label and record how many of each element are on each side of the equation. The first equation has 1 Ca, 2H, and 2Cl on both sides while the second equation has 3H on the left and 2H on the right making the second equation incorrect.
Answer:You can set up stoichiemetry using the following equation:
(15.6 g MgF2) x (38g F / 62g MgF2) x (6.022x10^23 / 19gF)
= 3.03 x 10^23 molecules of F
or 1.52 x 10^23 molecules of F2
The number of molecules of magnesium fluoride in 15.6 g of MgF2 has to be found.
The molecular mass of MgF2 is 62.3018. 15.6 g of MgF2 is equivalent to 15.6/62.3018 mole of MgF2.
One mole of a gas has 6.02214179*10^23 particles.
15.6/62.3018 mole of MgF2 has (15.6/62.3018)*6.02214179*10^23 molecules of the compound.
(15.6/62.3018)*6.02214179*10^23
=> 1.5079*20^23
If this is rounded to one decimal figure the result is 1.51*10^23.
The number of molecules of MgF2 in 15.6 g of the gas is 1.51*10^23.
Potential energy, kinetic energy would be if they were already running
Answer:
C4H8
Explanation:
First find the molar mass of CH2;
2(1.01) + 1(12.01) = 14.03g
Now divide the molar mass of the compound by the molar mass of CH2;
56g/14.03g = 3.9914 Round to nearest whole number = 4
Multiply CH2 by 4 to get the molecular formula;
CH2* 4 = C4H8
Answer:
No.
Explanation:
No, individual particles do not move with the wave, it only oscillates back and forth its mean position. The particles in the medium transfer its energy to their neighboring particles and in that way the energy moves in the form of wave. The particles only vibrates on its means position instead of moving from one place to another. So we can conclude that Individual particles do not move with the wave.
