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bija089 [108]
3 years ago
10

Hey need help. this is ONE question a 4 part one though. pls help

Chemistry
2 answers:
denpristay [2]3 years ago
4 0
A. Summer
B. Spring
C. Winter
D. Fall
shusha [124]3 years ago
3 0
I don’t get it. What is the question asking?
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Balance the following equation and find molar ratios from the equation,
Vikki [24]
To balance it, it would be N2 + 3H2 ------> 2NH3. 

for c) it would be 2N2 + 6H2 -------> 4NH3
7 0
3 years ago
Sort each of the following elements by effective nuclear charge, Zeff, from smallest to largest:
krek1111 [17]

Answer:

Rb = +1 , Sr = +2, In= +3,  Sn = +4, Sb= +5

Explanation:

Formula:

Zeff = Z - S

Z = atomic number

S = number of core shell or inner shell electrons

For Sn:

Electronic configuration:

Sn₅₀ = [Kr] 4d¹⁰ 5s² 5p²

Zeff = Z - S

Zeff = 50 - 46

Zeff = +4

For Rb:

Electronic configuration:

Rb₃₇ = [Kr] 5s¹

Zeff = Z - S

Zeff = 37 - 36

Zeff = +1

For Sb:

Electronic configuration:

Sb₅₁ = [Kr] 4d¹⁰ 5s² 5p³

Zeff = Z - S

Zeff = 51 - 46

Zeff = +5

For In:

Electronic configuration:

In₄₉ = [Kr] 4d¹⁰ 5s² 5p¹

Zeff = Z - S

Zeff = 49 - 46

Zeff = +3

For Sr:

Electronic configuration:

Sr₃₈= [Kr]  5s²

Zeff = Z - S

Zeff = 38 - 36

Zeff = +2

8 0
3 years ago
Indique el valor de los números n,l,m y s para el último electrón de ₇N.(1 pt c/u) n = _____ l = _____ m = _____ s =_____
tia_tia [17]

Answer:

n = 2

l = 1

m = 1

s = +1/2

Explanation:

₇N tiene la configuración electrónica;

1s2 2s2 2p3

Esto implica que este último electrón tiene los siguientes números cuánticos;

n = 2

l = 1

m = 1

s = +1/2

Este último electrón estará en un orbital de 2pz como lo muestran los números cuánticos enumerados anteriormente.

6 0
3 years ago
Two changes are described below. Ice melts to form water. Sugar cubes dissolve in hot coffee. Which statement is true about the
almond37 [142]

Answer:

both are physical changes

Explanation:

7 0
3 years ago
Read 2 more answers
If the mass of the baking soda before the reaction was 10 grams and the mass of the vinegar was 15 grams and all of the baking s
Masteriza [31]

Answer:

8.946g NaHCO₃,

14.475g H₂O,

1.025g CH₃COO⁻Na⁺,

0.500g CO₂.

Explanation:

Baking soda (NaHCO₃) reacts with vinegar (CH₃COOH 5%) producing  CH₃COO⁻Na⁺, H₂O and CO₂, thus:

NaHCO₃ + CH₃COOH → CH₃COO⁻Na⁺ + H₂O + CO₂

10g of NaHCO₃ are:

10g × (1mol / 84g) = 0.119 moles NaHCO₃

Moles of CH₃COOH in 15g of vinegar are:

15g vinegar × 5% = 0.75g CH₃COOH × (1mol / 60g) = 0.0125moles CH₃ COOH

After reaction, moles of NaHCO₃ that remains are:

0.119mol - 0.0125mol = <em>0.1065 moles NaHCO₃</em>

In mass:

0.1065mol ₓ (84g / 1mol) = <em>8.946g NaHCO₃</em>

Acetic acid reacts completely producing  0.0125moles of CH₃COO⁻Na⁺, water and CO₂. In mass:

CH₃COO⁻Na⁺ = 0.0125mol ₓ (82.03g / 1mol) = <em>1.025g CH₃COO⁻Na⁺</em>

H₂O = 0.0125mol ₓ (18.01g / 1mol) = <em>0.225g H₂O</em>

CO₂ = 0.0125mol ₓ (40g / 1mol) = <em>0.500g CO₂</em>

Now, 95% of vinegar is water (Doesn't react), that is:

15g × 95% = 14.25g H₂O. Total mass of water is:

14.25g + 0.225g = <em>14.475g H₂O</em>

<em></em>

Total mass is:

8.946g + 14.475g H₂O + 1.025g + 0.500g ≈ 25g. The same than initial mass following law of conservation of matter.

6 0
3 years ago
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