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Marysya12 [62]
3 years ago
12

Please help! BRAINLIEST to right answerrrr

Chemistry
2 answers:
zloy xaker [14]3 years ago
8 0

Answer: from the hotter surface to the colder one

Explanation:

timofeeve [1]3 years ago
7 0

Answer:d

d

Explanation:

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B) As water temp increases solubility increases
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Zinc metal (Zn) reacts with hydrochloric acid (HCI) to produce hydrogen gas (H) and zinc chloride (ZnCl2). A scientist has powde
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When is the next lunar Eclipse and how do they happen?
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6 0
3 years ago
The benzoate ion, c6h5coo− is a weak base with kb=1.6×10−10. how many moles of sodium benzoate are present in 0.50 l of a soluti
lyudmila [28]

NaC6H5COO \rightarrow Na{^{+}} + C6H5COO^{-}

Here the base is a benzoate ion, which is a weak base and reacts with water.

C6H5COO^{-}(aq) + H2O (l)\leftrightarrow C6H5COOH(aq)+ OH^{-}(aq)

The equation indicates that for every mole of OH- that is produced , there is one mole of C6H5COOH produced.

Therefore [OH-] = [C6H5COOH]

In the question value of PH is given and by using pH we can calculate pOH and then using pOH we can calculate [OH-]

pOH = 14 - pH

pH given = 9.04

pOH = 14-9.04 = 4.96

pOH = -log[OH-] or [OH^{-}] = 10^{^{-pOH}}

[OH^{-}] = 10^{^{-4.96}}

[OH^{-}] = 1.1\times 10^{-5}

The base dissociation equation kb = \frac{Product}{Reactant}

kb =\frac{[C6H5COOH][OH^{-}]}{[C6H5COO^{-}]}

H2O(l) is not included in the 'kb' equation because 'solid' and 'liquid' are taken as unity that is 1.

Value of Kb is given = 1.6\times 10^{-10}

And value of [OH-] we have calculated as 1.1\times 10^{-5} and value of C6H5COOH is equal to OH-

Now putting the values in the 'kb' equation we can find the concentration of C6H5COO-

kb =\frac{[C6H5COOH][OH^{-}]}{[C6H5COO^{-}]}

1.6\times 10^{-10} = \frac{[1.1\times 10^{-5}][1.1\times 10^{-5}]}{[C6H5COO^{-}]}

[C6H5COO^{-}] = \frac{[1.1\times 10^{-5}][1.1\times 10^{-5}]}{1.6\times 10^{-10}}

[C6H5COO^{-}] = 0.76 M or 0.76\frac{mol}{L}

So, Concentration of NaC6H5COO would also be 0.76 M and volume is given to us 0.50 L , now moles can we calculated as : Moles = M X L

Moles of NaC6H5COO would be = 0.76(\frac{mol}{L}) \times (0.50L)

Moles of NaC6H5COO (sodium benzoate) = 0.38 mol

8 0
3 years ago
Read 2 more answers
Polymers are large molecules composed of simple units repeated many times. Thus, they often have relatively simple empirical for
sp2606 [1]

Answer:

(a) C5H8O2

(b) C2H2Cl2

(c) CH2

(d) CH

Explanation:

We need to find the proportion of the atoms in whole numbers. Given the percentages we can calculate the number of moles and find their proportions.

Assume 100 g and given the atomic weights the moles are calculated.

(a) C = 59.9/ 12.01 = 4.98  ≈ 5.00

    H = 8.06/1.007 = 8.00

    O = 32/15.999  = 2.00

C5H8O2

(b) C= 24.8/12.01 = 2.06≈ 2.00

    H = 2.0/1.007 = 1.99 ≈ 2.00

   Cl = 73.1/ 35.453 = 2.06 ≈ 2.00

C2H2Cl2

(c) C = 86/12.01 = 7.16  

    H= 14/1.007 = 13.90

7.16:13.90 ≈ 1:2

CH2

(d) C = 92.30/12.01 = 7.68

    H = 7.7 / 1.007 =   7.65

7.68:7.65 ≈ 1:1

CH

6 0
3 years ago
Read 2 more answers
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