Answer:
D
Explanation:
A and C are physical changes, while B is a solution, only D is a chemical reaction.
Answer:
6CO2+6H2O->C6H12O6+6O2
Explanation:
CO2+H2O+C6H12O6+O2 This wrong when you write a formula. Don't savage the given question. caused it will affect the same answer.
It will write as this CO2+H20->C6H12O6+O2
So, Think what will you use the numbers in a side of chemical formula/name I am using the "eyes to eyes "caused you need to it properly. If you are not good at it use other method calculate each chemical name example. we have C=1,O=2 then, H=2,O=1 and they other side goes to the arrow is C=6 H=12O=6 ,O=2 I will think what number will make it balance for them and what is lucking see in the my answers what I add in the equation think carefully I didn't change or erase a number of them. Caused it is wrong if you do that. Thank you
<h3>
Answer:</h3>
Initial temperature is 243.59°C
<h3>
Explanation:</h3>
The quantity of heat is calculated by multiplying the mass of a substance by its specific heat capacity and change in temperature.
That is; Q = m×c×ΔT
In this case;
Quantity of heat = 560 J
Mass of the Sample of Zinc = 10 g
Final temperature = 100°C
We are required to determine the initial temperature;
This can be done by replacing the known variables in the formula of finding quantity of heat,
Specific heat capacity, c, of Zinc = 0.39 J/g.°C
Therefore,
560 J = 10 g × 0.39 J/g°C × ΔT
ΔT = 560 J ÷ (3.9 J/°C)
= 143.59°C
But, since the sample of Zinc lost heat then the temperature change will have a negative value.
ΔT = -143.59°C
Then,
ΔT = T(final) - T(initial)
Therefore,
T(initial) = T(final) - ΔT
= 100°C - (-143.59°C)
= 243.59°C
Hence, the initial temperature of zinc sample is 243.59°C
Answer: D. 4,6,4
Explanation:
The valence electron is the electron found in the outermost shell of an atom, and participates in bond formation.
For the following element, the valence electron can be noticed when we write the electronic configuration of each element.
Silicon = 1s2 2s2 2P6 3s2 3p2
Sulphur = 1s2 2s2 2P6 3s2 3p4
Germanium = 1s2 2s2 2P6 3s2 3p6 3d10 4s2 4p2