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Alex777 [14]
4 years ago
8

20 POINTS!!

Chemistry
2 answers:
Elza [17]4 years ago
4 0
The answer is option number one
Zolol [24]4 years ago
4 0
I think it would be B as your answer :)
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Reaction Rates
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Answer:

PART A 1st order in A and 0th order in B

Part B The reaction rate increases

Explanation:

<u>PART A </u>

The rate law of the arbitrary chemical reaction is given by

-r_A=k\times\left[A\right]^\alpha\times\left[B\right]^\beta\bigm

Replacing for the data

Expression 1 0.00639=k\times{0.12}^\alpha\times{0.22}^\beta

Expression 2 0.01280=k\times{0.24}^\alpha\times{0.22}^\beta

Expression 3 0.00639=k\times{0.12}^\alpha\times{0.11}^\beta

Making the quotient between the fist two expressions

\frac{0.00639}{0.01280}=\left(\frac{0.12}{0.24}\right)^\alpha

Then the expression for \alpha

\alpha=\frac{ln\frac{0.00639}{0.01280}}{ln\frac{0.12}{0.24}}=1\bigm

Doing the same between the expressions 1 and 3  

\frac{0.00639}{0.00639}=\left(\frac{0.22}{0.11}\right)^\beta

Then

\beta=\frac{ln\frac{0.00639}{0.00639}}{ln\frac{0.22}{0.11}}=0\bigm

This means that the reaction is 1st order respect to A and 0th order respect to B .

<u>PART B </u>

By the molecular kinetics theory, if an increment in the temperature occurs, the molecules will have greater kinetic energy and, consequently, will move faster. Thus, the possibility of colliding with another molecule increases. These collisions are necessary for the reaction. Therefore, an increase in temperature necessarily produces an increase in the reaction rate.

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How can the speed of solvent molecules be slowed down?
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Read 2 more answers
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