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Alex777 [14]
3 years ago
8

20 POINTS!!

Chemistry
2 answers:
Elza [17]3 years ago
4 0
The answer is option number one
Zolol [24]3 years ago
4 0
I think it would be B as your answer :)
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When developing an experimental design, which action would improve the
11111nata11111 [884]

Answer:

A

Explanation:

I'm right I took the test

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2 years ago
What is defined as the basic unit in the metric system that describes a quality
Bingel [31]

Answer:

They are:

Length - meter (m)

Time - second (s)

Amount of substance - mole (mole)

Electric current - ampere (A)

Temperature - kelvin (K)

Luminous intensity - candela (cd)

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3 years ago
What are the uses of carbon-14?
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6 0
3 years ago
A sample of bleach was analyzed as in this procedure. The only procedural difference is that the student weighed out the bleach
Bogdan [553]

Answer:

% = 5.69%

Explanation:

To do this, we need to write the equations taking place here. First, this is a REDOX reaction where the hypoclorite and thiosulfate solution reacts. The balanced equations are:

ClO⁻ + 2I⁻ + 2H⁺ -------> Cl⁻ +  I₂ + H₂O

I₂ + 2S₂O₃²⁻ -----------> 2I⁻ + S₄O₆²⁻

We already have the required volume and concentration of the thiosulfate solution, so we can calculate the moles of thiosulfate. With this moles, we can calculate the moles of hypochlorite, then the mass and finally the %.

The moles of thiosulfate would be:

moles S₂O₃²⁻ = V * M

moles S₂O₃²⁻ = 0.01324 * 0.0732 = 9.69x10⁻⁴ moles

Now according to the above reactions, we can see that

moles I₂ = moles ClO⁻

and

moles I₂ / moles S₂O₃²⁻ = 1/2

Therefore, let's calculate the moles of ClO⁻:

moles ClO⁻ = 9.69x10⁻⁴ / 2 = 4.845x10⁻⁴ moles

Now, we can calculate the mass of these moles, using the molar mass of sodium hypochlorite which is 74.44 g/mol:

m = 74.44 * 4.845x10⁻⁴

m = 0.036 g

Finally the % of this, in the bleach sample would be:

% = 0.036 / 0.634 * 100

<h2>% = 5.69%</h2>
6 0
3 years ago
What is another common name for the lanthanoids on the periodic table?
RUDIKE [14]
Lanthanide Lanthanoid, also called Lanthanide
7 0
3 years ago
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