Answer:
0.72 g of the lower oxide gave 0.8 g of higher oxide when oxidised. ... Thus, 90g of lower oxide contains as much metal as 100g of higher oxide, i.e., 80g (given). Hence, 80g of metal combines with 10g of oxygen in the lower oxide and 20g of oxygen in the higher oxide.
Answer:
Probably A.
Explanation:
Its either A or C. A is more probable imo
Answer is: mass of silver chloride is 34,82 g.
Chemical
reaction: AgNO₃ +
NaCl → AgCl + NaNO₃.
<span>m(AgNO</span>₃) = 53,42 g..<span>
m(NaCl) = 14,19 g.
n(AgNO</span>₃) = m(AgNO₃) ÷ M(AgNO₃).<span>
n(AgNO</span>₃) = 53,42 g ÷ 169,87 g/mol.
n(AgNO₃) = 0,314 mol.
n(NaCl) = 14,19 g ÷ 58,4 g/mol.
n(NaCl) = 0,242 mol; limiting reactant.
From chemical reaction: n(NaCl) : n(AgCl) = 1 : 1.<span>
n</span>(AgCl)<span> = 0,242 mol.
m</span>(AgCl) = 0,252 mol · 143,32 g/mol.
m(AgCl) = 34,82 g.
I think the answer is A or C sorry for not having that good of an answer
Explanation:
Balance the following equation: C3H8 + O2 ----> CO2 + H2O. (There will be no need for state symbols.) First of all, to balance these equations, list the number of each atom, for both sides of the equation. In this example, it would be: The first step would be to balance out the carbons on the products side by multiplying CO2 by 3. The balanced chemical equation for C3H8 +O2 = CO2 + H2O is C3H8 +5O2 = 3CO2 +4H2O. This is the chemical reaction in which C3H8 or propane burns in air or oxygen to produce carbon dioxide and water.
