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3 years ago

Why are summer days longer than winter days on earth?

Physics

2 answers:

german3 years ago

6 0

Answer:

The sun is father away during the winter.

Explanation:

In the northern hemisphere, during the winter it is summer in the southern hemisphere. The sun is farther away for us so the days get shorter in the winter since the sun inches away faster.

Aleks [24]3 years ago

3 0

Answer:

Tilt of the Earth

Explanation:

The Earth's rotational axis is titled at an angle 23.4°. When then northern hemisphere is pointed towards the Sun it is summer in the northern hemisphere and winter in the southern hemisphere.

In the northern hemisphere a day would be longer and gets more sunlight than the southern hemisphere.

The same happens when it is summer in the southern hemisphere.

You might be interested in

What will the magnitude of the field be if the 10 nc charge is replaced by a 20 nc charge? Assume the system is big enough to co

MArishka [77]

Answer:

Same magnitude of the 10 nc charge cause the electric field is external.

Explanation:

To do a better explanation, let's go and suppose we have an electric field of, 1300 N/C with a 10 nC charge.

As the system we are talking about is really big, and the charge is small, we can assume always if the charge is sitting right in the same point where the electric field is, then, the electric field would not suffer any kind of alteration in it's value. Therefore, no matter what value of the charge is sitting here, the electric field is independent of the charge, so it would not feel any alteration. However, the force that the charge is feeling would be stronger than in the first case.

F = qE

If charge is doubled, then the force would be bigger in the second case than in the first case, but electric field remain the same value.

4 0

3 years ago

A TV satellite broadcasts at a frequency of 5000 MHz, (1 MHz = 1 million Hertz). What is the wavelength of this radiation?

Nitella [24]

Answer:

$\lambda=0.06\ m$

Explanation:

Given:

frequency of the broadcast, $f=5000\ MHz=5\times 10^9\ Hz$

we have the speed of the radiation equal to the speed of light, $c=3\times 10^8\ m.s^{-1}$

The broadcast waves are the electromagnetic waves but it can travel only upto a hundred kilometers without any loss of information carried by it.

<u>The relation between the frequency and the wavelength:</u>

$\lambda=\frac{c}{f}$

$\lambda=\frac{3\times 10^8}{5\times 10^9}$

$\lambda=0.06\ m$

5 0

3 years ago

Read 2 more answers

When you open the front door to your warm house on a cold day, which way does the heat flow? For example, which is correct to sa

sashaice [31]

“Close the door, you’re letting the cold in!”

5 0

3 years ago

Read 2 more answers

2 Points

Tamiku [17]

Answer:

A. 0.32s

Explanation:

Lets find the initial velocity of the vertical component

Cos23=u/4

4cos23=1.6m/s

then time, t =2u/g

2×1.6/9.8

=0.32seconds

6 0

3 years ago

Read 2 more answers

3. Sodium-24 has a half-life of 15 hours. If a sample of sodium-24 has an

sattari [20]

Answer:

See explanation

Explanation:

From the formula;

0.693/t1/2 = 2.303/t log (Ao/A)

t1/2 = half life of Sodium-24

Ao = initial activity of Sodium-24

A= activity of Sodium-24 at time = t

So,

0.693/15 = 2.303/15 log (800/A)

0.0462 = 0.1535 log (800/A)

0.0462/0.1535 = log (800/A)

0.3 = log (800/A)

Antilog(0.3) = (800/A)

1.995 = (800/A)

A = 800/1.995

A = 401 Bq

ii) 0.693/15 = 2.303/30 log (800/A)

0.0462 = 0.0768 log (800/A)

0.0462/0.0768 = log (800/A)

0.6 = log (800/A)

Antilog (0.6) = (800/A)

3.98 = (800/A)

A = 800/3.98

A = 201 Bq

iii)

0.693/15 = 2.303/45 log (800/A)

0.0462 = 0.0512 log (800/A)

0.0462/0.0512 = log (800/A)

0.9 = log (800/A)

Antilog (0.9) = (800/A)

7.94 = (800/A)

A = 800/7.94

A= 100.8 Bq

iv)

0.693/15 = 2.303/60 log (800/A)

0.0462 = 0.038 log (800/A)

0.0462/0.038 = log (800/A)

1.216 = log (800/A)

Antilog(1.216) = (800/A)

16.44 = (800/A)

A = 800/16.44

A = 48.66 Bq

3 0

3 years ago