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3 years ago

What is gravitational potiental energy

Physics

2 answers:

professor190 [17]3 years ago

8 0

Answer:

In classical mechanics, the gravitational potential at a location is equal to the work per unit mass that would be needed to move the object from a fixed reference location to the location of the object. It is analogous to the electric potential with mass playing the role of charge.

Explanation:

Essentially, gravitational potential energy, is an energy an object has because of its position.

kogti [31]3 years ago

4 0

Gravitational potential energy is energy an object possesses because of its position in a gravitational field. The most common use of gravitational potential energy is for an object near the surface of the Earth where the gravitational acceleration can be assumed to be constant at about 9.8 m/s2.it is Gravitational energy is the potential energy held by an object because of its high position compared to a lower position. In other words, it is energy associated with gravity or gravitational force. bran-list please

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What is the length of a string with a mass of 2.5 kg, with a

natulia [17]

B 0.4 m should be correct if not it is A

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3 years ago

A sheet of metal is 2mm wide 10cm tall and 15cm long. it was 4g. what is the density? <br>

Hoochie [10]

Answer:

Ro = 133 [kg/m³]

Explanation:

In order to solve this problem, we must apply the definition of density, which is defined as the relationship between mass and volume.

$Ro = m/V$

where:

m = mass [kg]

V = volume [m³]

We will convert the units of length to meters and the mass to kilograms.

L = 15 [cm] = 0.15 [m]

t = 2 [mm] = 0.002 [m]

w = 10 [cm] = 0.1 [m]

Now we can find the volume.

$V = 0.15*0.002*0.1\\V = 0.00003 [m^{3} ]$

And the mass m = 4 [gramm] = 0.004 [kg]

$Ro = 0.004/0.00003\\Ro = 133 [kg/m^{3}]$

3 0

3 years ago

Correct the following statement:

ankoles [38]

Answer:

It's the 3rd option

Explanation:

Wind is caused by the differences in air pressure on Earth's surface.

4 0

3 years ago

An MRI scanner is based on a solenoid magnet that produces a large magnetic field. The magnetic field doesn't stop at the soleno

GaryK [48]

Answer:

The maximum change in flux is $\Delta \o = 0.1404 \ Wb$

The average induced emf $\epsilon =0.11232 V$

Explanation:

From the question we are told that

The speed of the technician is $v = 0.80 m/s$

The distance from the scanner is $d = 1.0m$

The initial magnetic field is $B_i = 0T$

The final magnetic field is $B_f = 6.0T$

The diameter of the loop is $D = 19cm = \frac{19}{100} = 0.19 m$

The area of the loop is mathematically represented as

$A = \pi [\frac{D}{2} ]^2$

$= 3.142 \frac{0.19}{2}$

$= 0.02834 m^2$

At maximum the change in magnetic field is mathematically represented as

$\Delta \o = (B_f - B_i)A$

=> $\Delta \o = (6 -0)(0.02834)$

$\Delta \o = 0.1404 \ Wb$

The average induced emf is mathematically represented as

$\epsilon = \Delta \o v$

$= 0.1404 * 0.80$

$\epsilon =0.11232 V$

7 0

3 years ago

a 75-kg refrigerator is located on the 70th floor of a skyscraper (300 meters above ground). what is the potential energy of the

mart [117]

Here, you can calculate it's potential energy with respect to ground.
We know, U = mgh
Here, m = 75 Kg
g = 9.8 m/s² [ constant value for earth system ]
h = 300 m

Substitute their values into the expression:
U = 75 × 9.8 × 300
U = 220500 J

In short, Your Final Answer would be 220,500 J

Hope this helps!

8 0

3 years ago

What is gravitational potiental energy​

What is gravitational potiental energy