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jeka94
3 years ago
5

Hot, solid rock in the Earth's crust a. is cooler than surface lava because of the pressure of overlying rock. b. maintains unif

orm composition as it melts and becomes magma. c. melts at a higher temperature if volatiles such as water and carbon dioxide are added. d. may melt if heat is transferred to it from hot mantle rock rising up into the crust.
Chemistry
1 answer:
mrs_skeptik [129]3 years ago
3 0

Answer:

d. may melt if heat is transferred to it from hot mantle rock rising up into the crust.

Explanation:

Hot, solid rock in the Earth's crust is a solid outer region of the Earth, Underneath the Earth Structure lies the mantle which is composed of solid rocks especially granite and basalt. The mantle is very hot and may melt if heat is transferred to it from hot mantle rock rising up into the crust therefore forming a molten magma. It may even be hotter (and not cooler as it was stated in the option A which makes it the wrong answer) than the surface lava because of the pressure of the overlying rock. As such, This effect is seen when a volcanic eruption occurs.

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Cyclopropane is more reactive than most cycloalkanes. What factors lead to cyclopropane being less stable than the other cycloal
maw [93]

Answer: The factor that lead to cyclopropane being less stable than the other cycloalkanes is the presence of a RING STRAIN.

Explanation:

In organic chemistry, the end carbon atoms of an open aliphatic chain can join together to form a closed system or ring to form cycloalkanes. Such compounds are known as cyclic compounds. Examples include cyclopropane, cyclobutane, cyclopentane and many among others.

Cyclopropane is less stable than other cycloalkanes mentioned above because of the presence of ring strain in its structural arrangement. The ring strain is the spatial orientation of atoms of the cycloalkane compounds which tend to give off a very high and non favourable energy. The release of heat energy which is stored in the bonds and molecules cause the ring to be UNSTABLE and REACTIVE.

The presence of the ring strain affects mainly the structures and the conformational function of the smaller cycloalkanes. cyclopropane, which is the smallest cycloalkane than the rest mentioned above, contains only 3 carbons with a small ring.

8 0
2 years ago
For a particular redox reaction, Cr is oxidized to CrO 2 − 4 and Ag + is reduced to Ag . Complete and balance the equation for t
Sunny_sXe [5.5K]

Answer:

6Ag⁺ + Cr + 8OH⁻ → 6Ag + CrO₄²⁻ + 4H₂O

Explanation:

We can balance the redox reaction of Cr and Ag⁺, in terms of two half-reactions, one for Ag⁺ and other for Cr:

Ag⁺   →   Ag      

In the above equation we need to balance the number of electrons, we know that the Ag⁺ is being reduced to Ag, so the reaction is:

Ag⁺ + e⁻ →  Ag   (1)

Now, we need to balance the half-reaction of Cr:

Cr   →  CrO₄²⁻  

From above, we know that the Cr is being oxidated to CrO₄²⁻, so we need to balance the number of electrons and the number of oxygen atoms. The Cr⁰ is being oxidated to Cr⁶⁺, so for the electron balance, we need to add 6e⁻ to the right side of the equation. Since the reaction is in a basic medium, the oxygen atoms will be balanced with OH⁻ ions as follows:          

Cr + OH⁻ →  CrO₄²⁻ + 6e⁻  

The hydrogen atoms will be balanced using H₂O molecules:  

Cr + OH⁻ →  CrO₄²⁻ + 6e⁻ + H₂O    

The balanced equation is:

Cr + 8OH⁻ →  CrO₄²⁻ + 6e⁻ + 4H₂O   (2)

Since the reaction (1) involves 1 electron and the reaction (2) involves 6 electrons, by increasing the reaction (1) six times and by the addition of the two reactions (1 and 2) we can have the net redox reaction:

6*(Ag⁺ + e⁻ →  Ag)  

<u>Cr + 8OH⁻ →  CrO₄²⁻ + 6e⁻ + 4H₂O</u>

6Ag⁺ + Cr + 8OH⁻ → 6Ag + CrO₄²⁻ + 4H₂O                  

Therefore, the net equation is: 6Ag⁺ + Cr + 8OH⁻ → 6Ag + CrO₄²⁻ + 4H₂O.

I hope it helps you!

7 0
3 years ago
How do I convert 498.82 cg to mg
Rus_ich [418]
498.82 cg ( mg
4988.2 mg
6 0
3 years ago
Read 2 more answers
A sample of hydrogen gas collected over water occupied 30.0 mL at 24 °C on a day when the atmospheric pressure was 736 Torr. Wha
givi [52]

Answer:0.026ml

Explanation:

Details are found in the image attached. We must subtract the saturated vapour pressure of hydrogen gas at the given temperature from the total pressure of the hydrogen gas collected over water to obtain the actual pressure of hydrogen gas and substitute the value obtained into the general gas equation. The dry hydrogen gas has no saturated vapour pressure hence the value is substituted as given. All temperatures must be converted to Kelvin before substitution.

4 0
3 years ago
How many moles of aspartame are present in 1.00 mg of aspartame?
Diano4ka-milaya [45]

Answer:- There are 3.40*10^-^6 moles.

Solution:- It is a unit conversion problem where we are asked to convert mg of aspartame to moles. Aspartame is C_1_4H_1_8N_2O_5 and it's molar mass is 294.31 grams per mole.

mg are converted to grams and then the grams are converted to moles as:

1.00mg Aspartame(\frac{1g}{1000mg})(\frac{1mole}{294.31g})

= 3.40*10^-^6 moles of aspartame

So, there would be 3.40*10^-^6 moles of aspartame in 1.00 mg of it.

3 0
3 years ago
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