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slavikrds [6]
4 years ago
13

What are the intermolecular forces present in Argon?

Chemistry
1 answer:
Lina20 [59]4 years ago
5 0
The intermolecular forces that is present in Argon are dispersion forces. There is no other intermolecular forces present. There will be no hydrogen bonding since there is no hydrogen. No dipole-dipole because there are no dipole moments.
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In ______ observation, EVERY INDIVIDUAL in a population is counted. In _________ observation, SIGNS OF AN INDIVIDUAL, such as tr
larisa86 [58]

Answer:

In direct observation, EVERY INDIVIDUAL in a population is counted. In indirect observation, SIGNS OF AN INDIVIDUAL, such as tracks or nests, are counted.

Explanation:

Direct observation is to involve looking at the actual behavior or occurrence so for your question it would be every individual.

Indirect observation is a result of that occurrence, so for your question it would be the signs of an individual.

8 0
4 years ago
Why boron trifluoride is nonpolar and sulphur dioxide is polar
ella [17]

it small because that bond is not very polar notice that all of those arrows they cancel. because they point in opposite directions. that's why BH 3 is nonpolar if we were to draw the Lewis structure of bf3. ... so even though the boron fluorine bond is polar the molecule as a whole is nonpolar.

6 0
3 years ago
The density of table salt is 2.16 g/cm3. Detail the conversion into units of pounds per liter, and provide the density in lb/L.
Leona [35]

Answer:

density = 4.763pounds per liter

Explanation:

1g/cm³ = 2.205pounds per liter

2.16g/cm³ = (unknown)pounds per liter

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density = 4.763pounds per liter

4 0
3 years ago
The law of conservation of matter states that matter is neither created nor destroyed in a chemical reaction. Which of the follo
Artyom0805 [142]

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A

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4 0
3 years ago
Read 2 more answers
A solution is prepared by adding 0.0231moles of H3O+ ions to 3.33L of water. What is the pH of this solution
MrMuchimi

Answer:

2.15

Explanation:

For this question, we have to remember the <u>pH formula</u>:

pH~=~-Log[H_3O^+]

By definition, the pH value is calculated when we do the -Log of the concentration of the <u>hydronium ions</u> (H_3O^+). So, the next step is the calculation of the <u>concentration</u> of the hydronium ions. For this, we have to use the <u>molarity formula</u>:

M=\frac{mol}{L}

We already know the number of moles (0.0231 moles) and the volume (3.33 L). So, we can plug the values into the molarity formula:

M=\frac{0.0231~moles}{3.33~L}=0.00693~M

With this value, now we can calculate the pH value:

pH~=~-Log[0.00693~M]~=~2.15

<u>The pH would be 2.15</u>

I hope it helps!

8 0
3 years ago
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