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3 years ago

13

What are the intermolecular forces present in Argon?

1 answer:

Lina20 [59]3 years ago

5 0

The intermolecular forces that is present in Argon are dispersion forces. There is no other intermolecular forces present. There will be no hydrogen bonding since there is no hydrogen. No dipole-dipole because there are no dipole moments.

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Liquid 1 has a density of 2.0 g/ml, Liquid 2

Natali5045456 [20]

Liquid 2 because the lower the density the more it floats and the higher the density the more it sinks. The order from top to bottom is liquid 2, liquid 3, liquid 1

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3 years ago

If a bullet travels at 407.0 m/s, what is its speed in miles per hour? Number click to edit mi/h For the same bullet travelling

kaheart [24]

Answer : The speed in miles per hour is 22 mile/hr.

The speed in yard per min is 26617.8 yard/min

Explanation :

The conversion used for meters to miles is:

$1m=100cm\times \frac{1in}{2.54cm}\times \frac{1ft}{12in}\times \frac{1mile}{5280ft}$

The conversion used for second to hour is:

$1s=\frac{1}{60}min\times \frac{1hr}{60min}$

The conversion used for meter per second to mile per hour is:

$1\frac{m}{s}=\frac{100cm\times \frac{1in}{2.54cm}\times \frac{1ft}{12in}\times \frac{1mile}{5280ft}}{\frac{1}{60}min\times \frac{1hr}{60min}}$

As we are given the speed of 407.0 meter per second. Now we have to determine the speed in miles per hour.

$1m/s=2.2mile/hr$

So, $407.0m/s=\frac{2.2mile/hr}{1m/s}\times 407.0m/s=895.4mile/hr$

Therefore, the speed in miles per hour is 22 mile/hr.

The conversion used for meter to yard

1m = 1.09 yard

The conversion used for second to hour is:

$1s=\frac{1}{60}min$

The conversion used for meter per second to mile per hour is:

$1m/s=\frac{1.09yard}{frac{1}{60min}}$

$1m/s=65.4yard/min$

As we are given the speed of 407.0 meter per second. Now we have to determine the speed in yards per min

$1m/s=65.4yard/min$

So, $407.0m/s=\frac{65.4yard/min}{1m/s}\times 407.0m/s=26617.8yard/min$

Therefore, the speed in yard per min is 26617.8 yard/min

7 0

2 years ago

How many mL of 1.50 M hydrochloric acid will neutralize 25 mL of 2.00 sodium hydroxide?

Lostsunrise [7]

Answer: The Answer is 18.7ml.

Explanation: Solved in the attached picture.

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3 years ago

Which is the correct set of products for the acid-base neutralization reaction between sulfuric acid (H2SO4) and potassium hydro

Elis [28]

Answer:

H2O and K2SO4

Explanation:

3 0

2 years ago

How many mole are in 72.9g of HCI

fredd [130]

Divide by the molar mass of HCl which is 36.5g/mol grams cancels out and you are left with 1.99 mol.

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3 years ago