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kirill115 [55]
3 years ago
10

A heat engine is designed to do work. This is possible only if certain relationships between the heats and temperatures at the i

nput and output hold true. Which of the following sets of statements must apply for the heat engine to do work?
A) Qh < Qc and Th < Tc
B) Qh > Qc and Th < Tc
C) Qh < Qc and Th > Tc
D) Qh > Qc and Th > Tc
Physics
2 answers:
Oduvanchick [21]3 years ago
8 0

Answer:

For the heat engine to do work. The quantity of heat in the hot reservoir (Qh) must be greater than the quantity of heat in the cold reservoir (Qc). So also, the temperature of the hot reservoir (Th) is greater than the temperature of the cold reservoir (Tc).

Therefore the correct answer is option (D)

Qh > Qc and Th > Tc

Explanation:

One of the general ways to illustrate a heat engine is the energy reservoir model. The engine takes energy from a hot reservoir and uses part of it to do work, but is constrained by the second law of thermodynamics to exhaust part of the energy to a cold reservoir. In the case of the automobile engine, the hot reservoir is the burning fuel and the cold reservoir is the environment to which the combustion products are exhausted. The efficiency of the heat engine is given as:

(W/Qh) = (Qh - Qc)/Qh

yuradex [85]3 years ago
7 0

Answer: B

Explanation:

Qh>Qc and Th>Tc is the right condition for heat engine to operate since it needs heat.

It obtains this heat input (Qh) through a high temperature heat reservoir (Th). It takes some of this heat and does work, and releases the rest of the heat (Qc) to a low temperature heat reservoir (Tc)

For energy balance on a heatbengine, we obtain the following equation

Qh=W+Qc

Therefore if Qh is less than Qc, we get negative work, meaning we have to put work into our engine (obviously not the purpose of a engine). So Qh>Qc. As for the temperature, the high temperature has to be higher than the low temp reservoir for heat to flow, as heat flows from high to low, and never the other way around (Clausius Second Law Statement).

In other words heat flows from a hotter body to a cooler body, that is the principle under which heat engine operate

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goldenfox [79]

Answer:

The impulse of the net force on the ball during its collision with the wall is 25N

Explanation:

Step one :

Given data

Mass =5kg

Velocity v1=10m/s

Velocity v2=5m/s

The equation for impulse is given as

P=m(v1-v2)

Where P =impulse

Substituting our values into the equation we have

P=5*(10-5)

P=5*5

P=25N

The impulse 25N

What is impulse?

Impulse is the change of momentum of an object when the object is acted upon by a force for an interval of time.

8 0
4 years ago
A 2.0 mass has j of kinetic energy <br> What is the speed?
Ad libitum [116K]

Answer:

v= 4.8 m/s

Explanation:

m= 2.0

KE= 1/2 mv^2

v= ?

v= 1/2 (2.0)^2

v= 4.8 m/s

3 0
3 years ago
Problem 7.17 A horizontal spring with stiffness 0.8 N/m has a relaxed length of 12 cm (0.12 m). A mass of 23 grams (0.023 kg) is
Jlenok [28]

The speed of the mass v = 0.884 m/s.

<u>Explanation</u>:

Let

K1 represents the kinetic energy of the mass when it is released,

U1 represents the potential energy of the spring when the mass is released,

K2 represents the kinetic energy of the mass when the spring returns to relaxed length,

U2 represents the potential energy of the spring when the spring returns to relaxed length

The spring is stretched by 0.27 - 0.12 = 0.15 m

                                K1 = 0

                                 U1 = (1/2) \times 0.8 \times (0.15)^2

                                     = 0.009 J

                                U2 = 0

By conservation of energy,

                        K2 + U2 = K1 + U1

                           K2 + 0 = 0 + 0.009 J

                                 K2 = 0.009 J

Let v = speed of the mass

                                K2 = 1/2 \times m \times v^2

m = 23 g = 0.023 kg

                           0.009 = 1/2 \times 0.023 \times v^2

                           0.009 = 0.0115 \times v^2

                                   v = √(0.009 / 0.0115)

                                  v = 0.884 m/s.

5 0
4 years ago
A light-rail commuter train speeds up at a rate of 1.65 m/s 2 and takes 19.0 s to reach its top speed. How far down the tracks d
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Answer:

297.8 m

Explanation:

We are given that

Acceleration=a=1.65m/s^2

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We have to find the distance covered by the train when it reach its top speed if starting from rest.

Initial speed=u=0

s=ut+\frac{1}{2}at^2

Using the formula

s=0(19)+\frac{1}{2}\times 1.65(19)^2

s=297.8 m

Hence, the train covered 297.8 m when the train go to reach its top speed if starting from rest.

7 0
3 years ago
Magnesium (Mg) has 12 protons and an atomic mass of 24. How many neutrons does magnesium have?
JulijaS [17]
An atom is made up of three different particles, which are proton, neutron and electron. The proton and the neutron are located in the nucleus of the atom and they make up mass of the atom. The electron orbit around the nucleus. The proton is positively charged while the electron is negatively charged, thus, for the atom to remain neutral, the number of proton and electron in an atom must be equal. The neutron has no charge.
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Therefore, number of neutron = 24 - 12 = 12.
Thus, the number of neutron = 12.
5 0
3 years ago
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