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OLEGan [10]
3 years ago
8

Explain in terms of atomic structure why the radius of a cesium ion in cesium chloride is smaller than the radius of a cesium at

om when both are in the ground state
Cesium is further down on the periodic table.
Cesium has more electron shells than Rubidium
Cesium has more protons than Rb.
Cs has more valence shells than Rb
Chemistry
1 answer:
Yuri [45]3 years ago
3 0

Answer:

It has fewer electron shells

Explanation:

Cesium is a metal and metals tend to lose their valence electrons to become positively charged cations. Loss of valence electrons in a metal also results in the loss of the total valence shell. Therefore, when cesium loses its valence electron, it also loses the whole outer shell which consequently leads to a decrease in radius.

Therefore, we may conclude that for a fewer electron shells, we would expect to have a smaller radius.

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lisov135 [29]

Options found from another source are:

a. oxygen. b. glucose. c. energy stored as ATP. d. carbon dioxide and water

Answer:

c energy stored as ATP

Explanation:

Cellular respiration converts glucose into energy in the form of ATP (c). The answer cannot be oxygen (a), because this is required for this process as a final electron acceptor. In terms of photosynthesis, oxygen is released as a by-product. The answer cannot be glucose (b) because that is our starting point for respiration, and what is synthesised during photosynthesis. The answer cannot be (d) as carbon dioxide and water are released by cellular respiration, and required by photosynthesis

8 0
3 years ago
Calculating Density Warm Up
Artist 52 [7]

Answer:

2

Explanation:

33-25=8

48/8=6

6 0
3 years ago
Which location of the moon relative to the sun and earth may produce a warning (getting smaller nightly) half moon
scZoUnD [109]

Answer:

The moon to the direct right of the Earth relative to the Sun

Explanation:

6 0
3 years ago
Is 2AI + 3O2 = 2AI2O3 balanced or unbalanced?
Luba_88 [7]
This equation is balanced.
3 0
3 years ago
Give the electron configuration for the following atoms using appropriate noble gas inner core abbreviation: Bi Cr Sr P 2. Give
malfutka [58]

Answer:

See explanation

Explanation:

The noble gas core electron configuration involves writing the inert gas core of an atom followed by the valence electrons. This is shown for the following atoms;

Bismuth;

[Xe]4f14 5d10 6s2 6p3

Chromium;

[Ar]4s1 3d5

Strontium;

[Kr]5s2

Phosphorus;

[Ne]3s2 3p3

2.

Bi

6p- n=6, l= 1, ml= 1, ms= 1/2

Cr

3d- n=3, l=2, ml=2,ms=1/2

Sr

5s- n=5, l=0, ml=0, ms=1/2

P

3p- n=3, l= 1, ml= 1, ms=1/2

3.

a) Tin (Sn) - [Kr] 5s2 4d10 5p2

b) Caesium (Cs)- [Xe] 6s1

c) Copper (Cu)- [Ar] 4s1 3d10

4 0
2 years ago
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