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OLEGan [10]
3 years ago
8

Explain in terms of atomic structure why the radius of a cesium ion in cesium chloride is smaller than the radius of a cesium at

om when both are in the ground state
Cesium is further down on the periodic table.
Cesium has more electron shells than Rubidium
Cesium has more protons than Rb.
Cs has more valence shells than Rb
Chemistry
1 answer:
Yuri [45]3 years ago
3 0

Answer:

It has fewer electron shells

Explanation:

Cesium is a metal and metals tend to lose their valence electrons to become positively charged cations. Loss of valence electrons in a metal also results in the loss of the total valence shell. Therefore, when cesium loses its valence electron, it also loses the whole outer shell which consequently leads to a decrease in radius.

Therefore, we may conclude that for a fewer electron shells, we would expect to have a smaller radius.

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Calculate the number of moles of Cl2 produced at equilibrium when 3.98 mol of PCl5 is heated at 283.9 deg celsius in a vessel ha
ddd [48]

Answer:

1.274 moles

Explanation:

The equation for the reaction can be represented as follows:

                       PCl_5(g)           ⇄       PCl_3(g)     +         Cl_2(g)

K = 0.060

K = \frac{[PCl_3][Cl_2]}{[PCl_5]}

Concentration of   PCl_5(g)  = \frac{numbers of moles}{volume}

Concentration of   PCl_5(g)  = \frac{3.98}{10.0}

Concentration of   PCl_5(g)  = 0.398 moles

If we construct an ICE table for the above equation; we have:

                       PCl_5(g)           ⇄       PCl_3(g)     +         Cl_2(g)

Initial                0.398                          0                          0

Change            - x                               + x                        + x

Equilibrium    (0.398 - x)                      x                          x

K = \frac{[PCl_3][Cl_2]}{[PCl_5]}

K = \frac{[x][x]}{[0.398-x]}

K = \frac{x^2}{0.398-x}

0.060 = \frac{x^2}{0.398-x}

0.06(0.398-x) = x²

0.02388 - 0.060x = x²

x² + 0.060x - 0.02388 = 0               (quadratic equation)

a = 1;       b= 0.06;      c= -0.02388

Using quadratic formula;

=  \frac{-b+/-\sqrt{b^2-4ac} }{2a}

= \frac{-0.06+/-\sqrt{(0.06)^2-4(1)(-0.02388)} }{(2*1)}

= \frac{-0.060+/-\sqrt{0.0036+0.09552} }{2}

= \frac{-0.06+/-\sqrt{0.09912} }{2}

= \frac{-0.06+/-0.3148}{2}

= \frac{-0.060+0.3148}{2}   or \frac{-0.060-0.3148}{2}

= \frac{0.2548}{2}  or \frac{-0.3748}{2}

= 0.1274 or -0.1874

We go by the positive value which says:

[x] = 0.1274 M

number of moles = 0.1274 × 10.0

= 1.274 moles

∴ the number of moles  of Cl₂ produced at equilibrium = 1.274 moles

7 0
3 years ago
Look this is a weird question to ask but am asking it anyways
natali 33 [55]

You can wait until he either breaks up (if he does) or if just forget about him and go for another guy.

3 0
3 years ago
Read 2 more answers
Given 2.91 moles of a gas in a 500 milliliter-container, if the temperature is found to be 31 degrees Celsius, what is the press
kari74 [83]
Use the PV = nRT equation T is in Kelvins = 31 + 273 = 304 K

P(0.5) = (2.91)(0.0821)(304)
P(0.5) = 72.6289
P = 145.25 atm or 1.45x10^2 atm
3 0
3 years ago
Read 2 more answers
In breckenridge, colorado, the typical atmospheric pressure is 520. torr. what is the boiling point of water (hvap 40.7 kj/mol)
Art [367]
<span>362.51 Kelvin ln (p1/p2) =( dH / R) (1/T2 - 1/T1) ln (760 Torr /520Torr) =( 40,700 Joules / 8.314 J molâ’1K-1)(1/T2 - 1/373K) ln (1.4615) =( 4895.35)(1/T2 - 0.002681) 0.37946 = 4895.35/T2 - (0.002681)(4895.35) 0.37946 = 4895.35/T2 - (13.124) 0.37946 + 13.124 = 4895.35/T2 13.5039 = 4895.35/T2 T2 = 4895.35 / 13.5039 T2 = 362.51 answer is 362.51 Kelvin - 273 answer is also 89.5 Celsius</span>
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3 years ago
Most chemical reactions can be classified as one of four types. Using the chemical equations in the Gizmo as a guide, match the
Lostsunrise [7]

Answer:

<h2>The sequence is; b, e, a, d, c </h2>

Explanation:

1. In a decomposition reaction; One reactant is broken down into two or more than two products is called decomposition.

2. A combustion reaction; A fuel is combined with oxygen to produce carbon dioxide and water, this reaction is called combustion reaction.

3. A synthesis reaction; it occurs when two or more reactants combine to form one product is known as synthesis reaction.

4. Double Replacement Reaction; Two compounds react to form two different compounds is known as double Replacement Reaction.

5.  A single replacement reaction; occurs when a compound reacts with an element to form a new compound , this reaction is called as  single replacement reaction.

3 0
3 years ago
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