Answer:Increased the number of molecular collisions and increased the reaction rate
Explanation:
Answer : The mass of sucrose added to water will be, 189.0 grams.
Explanation :
As we are given that 9 % solution (mass per volume) that means 9 grams of sucrose present in 100 mL volume of solution.
Total given volume of solution = 2.1 L = 2100 mL (1 L = 1000 mL)
Now we have to determine the mass of sucrose in solution.
As, 100 mL of solution contains 9 grams of sucrose
So, 2100 mL of solution contains 
grams of sucrose
Therefore, the mass of sucrose added to water will be, 189.0 grams.
Answer:
The correct answer is 1.33 x 10⁻⁵ M
Explanation:
The concentration of the stock solution is: C= 1.33 M
In the first dilution, the student added 1 ml of stock solution to 9 ml of water. The total volume of the solution is 1 ml + 9 ml = 10 ml. So, the first diluted concentration is:
C₁= 1.33 M x 1 ml/10 ml = 1.33 M x 1/10 = 0.133 M
The second dilution is performed on C₁. The student added 1 ml of 0.133 M solution to 9 ml of water. Again, the total volume is 1 ml + 9 ml = 10 ml. The second diluted concentration is:
C₂= 0.133 M x 1 ml/10 ml = 0.133 M x 1/10= 0.0133 M
Since the student repeated the same dilution process 3 times more (for a total of 5 times), we have to multiply 5 times the initial concentration by the factor 1/10:
Final concentration = initial concentration x 1/10 x 1/10 x 1/10 x 1/10 x 1/10
= initial concentration x (1/10)⁵
= 1.33 M x 1 x 10⁻⁵
= 1.33 x 10⁻⁵ M
I believe the mesosphere, asthenosphere,
ionosphere.
Due to having lost fewer electrons than Fe3+, Fe2+ is larger. As a result, Fe3+ has a stronger nuclear pull, which causes the atomic size to decrease. As a result, Fe2+ is bigger.
The effective distance of an ion's nucleus from which it can influence its electron cloud is known as its ionic radius. Due to the removal of one or more electrons from the equivalent atom, a cation is usually substantially smaller than the corresponding atom. Additionally, the size of the resulting positive ion will be less the more electrons are removed.
Since the residual inner shell does not reach as far into space, a cation generated by the loss of electrons may cause the outer shell to completely vanish.
Learn more about electrons here-
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